Question

4. What is the electric field strength 1.4 nm from a charge of 4.7 cC?

Answer 1

The electric field strength is $2.16\cdot 10^{26} N/C$

Explanation:

The strength of the electric field produced by a single point charge is given by:

$E=k\frac{q}{r^2}$

where

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge at which the field strength is calculated

For the charge in the problem, we have:

$q=4.7 cC = 0.047 C$ is the charge

$r=1.4 nm = 1.4\cdot 10^{-9} m$

Therefore, the electric field strength is

$E=(8.99\cdot 10^9)\frac{0.047}{(1.4\cdot 10^{-9})^2}=2.16\cdot 10^{26} N/C$

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