Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation.
To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign.
Pb(s) --> Pb2+ +2e- E0 = +0.13 V
Ag+ + e- ---> Ag E0 = +0.80 V
Adding up the E0's would yield an overall electric cell potential of +0.93 V.
Answer:
1.55 mol
Step-by-step explanation:
We can use the <em>Ideal Gas Law</em> to solve this problem.
pV = nRT Divide both sides by RT
n = (pV)/(RT)
Data:
p = 1.40 atm
V = 27.5 L
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = 302 K
Calculations:
n = (1.40 × 27.5)/(0.082 06 × 302)
= 1.55 mol
Answer:
Difference in temperature
Explanation:
Temperature is the degree of hotness or coldness of a body. The difference in temperature between two bodies enables heat transfer from the hotter body to the colder one. If two bodies are at the same temperature, heat transfer will not occur between them. This why in the vicinity of hot water, a cold water becomes warmer.
mass is the answer 110% sure hope this helps
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NACL0.
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