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4 years ago

In most cases, how many electrons does it take to completely fill the

Physics

1 answer:

Lyrx [107]4 years ago

4 0

Answer: 2

Explanation:

Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. The general formula is that the nth shell can in principle hold up to 2(n2) electrons.

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A ray of light (f = 5.09 x 1014 Hz) is incident on the boundary between air and an unknown material X at an angle of incidence o

11Alexandr11 [23.1K]

Answer:

A) Material X is flint glass

B) Speed of light in the X material is 1.807 x $10^{8}$ m/s

C) Angle of refraction of light in medium X is $29.57^{o}$

Explanation:

Given data:

frequency of the light f = 5.09 x $10^{14}$ Hz

angle of incidence Θ $_{i}$ = $55^{o}$

index of refraction of material $n_{2}$ = 1.66

A) To find material X

Given the index of refraction is 1.66 and hence the material is the flint glass

B) To calculate the speed of light in the material.

We know that the relation between index of refraction (n), velocity of light (c = 3 x $10^{8}$ m/s) and velocity of light is given by the equation:

n = c/v

Hence,

Speed of light in the X material v = c/n

= $\frac{3 x 10^{8} }{1.66}$

= 1.807 x $10^{8}$ m/s

C) To calculate angle of refraction of light in medium X

We know that the Snell's law states that

$n_{1} sin$ Θ $_{i}$ = $n_{2} sin$ Θ $_{r}$

$n_{1}$ = incident index

$n_{2}$ = refracted index

Θ $_{i}$ = incident angle

Θ $_{r}$ = refracted angle

In given problem, $n_{1}$ = 1 since medium is air

Substituting the known values, we get

1 x $sin$ $55^{o}$ = 1.66 x $sin$ Θ $_{r}$

$sin$ Θ $_{r}$ = $sin$ $55^{o}$ /1.66

= 0.4935

Hence, angle of refraction of light in medium X Θ $_{r}$ = $sin^{-1}$ (0.4935)

= $29.57^{o}$

4 0

3 years ago

Two large parallel conducting plates are 8.0 cm apart and carry equal but opposite charges on their facing surfaces. The magnitu

Pepsi [2]

Answer:

18.1 V

Explanation:

The electric field between two parallel plates is given by the equation:

$E=\frac{\sigma}{\epsilon_0}$

where

$\sigma$ is the charge surface density

$\epsilon_0 = 8.85\cdot 10^{-12} F/m$ is the vacuum permittivity

For the plates in this problem,

$\sigma = 2.0 nC/m^2 = 2.0\cdot 10^{-9} C/m^2$

So, the magnitude of the electric field is

$E=\frac{2.0\cdot 10^{-9}}{8.85\cdot 10^{-12}}=226.0 V/m$

Now we can find the potential difference between the plates, which is given by

$\Delta V = E d$

where

d = 8.0 cm = 0.08 m is the separation between the plates

Substituting,

$\Delta V=(226.0)(0.08)=18.1 V$

8 0

3 years ago

Please help me on this!

alexgriva [62]

Answer:

3rd answer

Explanation:

compare the total amount of time for each student

8 0

3 years ago

Help ASAP <br> Just answer the first question for me please!

Usimov [2.4K]

Answer:

Im pretty sure its b

4 0

3 years ago

A 200g piece of iron is heated at 100C. It is than dropped into water to bring its temperature down to 22C. What is the amount o

gizmo_the_mogwai [7]

Answer:

6926.4J

Explanation:

Given parameters:

Mass of iron = 200g

Initial temperature = 100°C

Final temperature = 22°C

Unknown:

Amount of heat transferred to the water = ?

Solution:

The quantity of heat transferred to the water is a function of mass and temperature of the iron;

H = m c Ф

m is the mass of the iron

Ф is the change in temperature

C is the specific heat capacity of iron = 0.444 J/g°C

Now;

insert the parameters and solve;

H = 200 x 0.444 x (100-22)

H = 6926.4J

8 0

3 years ago