I have honestly never read anything about a car being disseminated,
or any instructions on how to do it, or any of the theory behind it.
The reverberation time with 800 audiences is 0.875 seconds.
<h3>
Reverberation time with 800 audience</h3>
R₁V₁ = R₂V₂
where;
- R₁ is the reverberation time with 400 audience
- R₂ is the reverberation time with 800 audience
- V₁ is initial volume
- V₂ is final volume
R₂ = R₁V₁/V₂
R₂ = (1.4 x 500) / 800
R₂ = 0.875 seconds
Thus, the reverberation time with 800 audiences is 0.875 seconds.
Learn more about reverberation time here: brainly.com/question/9278479
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10 x 4^2 = 160 / 8..
V = 20m/s...
...x 8 = 100 miles,meters, metric what ever m stands for after 8 seconds.
This is my guess since the problem says 4m/s^2
V= distance/ ST (traveled/used)
Sum the forces in the y (upward) direction




Applying the kinematic equations of linear motion we have that the displacement as a function of the initial speed, acceleration and time is



Again through the kinematic equation of linear motion that describes velocity as the change of displacement in a given time, we have to



Therefore the horizontal distance between the target and the rocket should be 38.83m
For the first one, the correct answer would be "<span>Substance changes its form but not its molecular composition.". During a physical change (let's say cutting paper), the substance has its shape changed, but it is still itself (paper).
</span><span>The second one is a bit trickier: </span>
Kinetic energy of a molecule is directly influenced by temperature. If there is a higher temperature it will have a higher kinetic energy which means the molecule moves at a higher velocity. This will increase the chance of particles bouncing off of each other during the chemical reaction. That explains why the rate of reaction will be higher at a higher temperature, rather than higher at a cool temperature. The correct answer would be lower at 39F.