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pav-90 [236]
3 years ago
7

What is the correct mathematical relationship between the number of moles, the volume, and the standard molar volume of a substa

nce?
Chemistry
2 answers:
masha68 [24]3 years ago
8 0
N=V/Vm

n - the number of moles
V - the volume
Vm=22.4 L/mol - the standard molar volume of gas
zvonat [6]3 years ago
3 0

Answer: {\text {no of moles}}=\frac{\text {Given volume}}{\text {Standard Molar volume}}

Explanation:

According to Avogadro's law, 1 mole of every gas occupies 22.4 L of volume at standard temperature and pressure conditions.

Thus Standard molar volume of substance= 22.4 L

To calculate the moles from mass ,we use the formula:

{\text { no of moles}}=\frac{\text{Given mass}}{\text{Molar mass}}

To calculate the moles from volume ,we use the formula:

Similarly, {\text {no of moles}}=\frac{\text {Given volume}}{\text {Standard Molar volume}}

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In Thomson’s model of the atom , what parts of the atom were in motion
trasher [3.6K]

Answer:

The electrons where in motion

4 0
3 years ago
Breathing equipment used by rescue workers needs to capture the CO2 the humans breath out and produce O2 for them to breath in,
const2013 [10]

Answer: 4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation for reaction of potassium superoxide  with carbon dioxide to produce oxygen and potassium carbonate will be:

4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2

8 0
2 years ago
A horizontal pipe 15 cm in diameter and 4 m long is buried in the earth at a depth of 20 cm. The pipe-wall temperature is 75 deg
Basile [38]

Explanation:

The given data for case (1) is as follows.

  h = 20 cm = 0.2 m

Assuming that a rectangular slab is placed above the pipe and we will calculate the heat transfer as follows.

              Q = kA \frac{\Delta T}{L}

  where,    A = area

                  L = length

                  k = thermal conductivity = 0.8 W/m

             \Delta T = change in temperature.

Therefore, putting the given values into the above formula as follows.

            Q = kA \frac{\Delta T}{L}

                = 0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{0.2}

                = 168 W

For case (2), h = 180 cm = 1.8 m

Therefore, heat lost will be calculated as follows.

                       Q = kA \frac{\Delta T}{L}

                           = 0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{1.8}

                           = 18.67 W

Thus, we can conclude that 18.67 W heat lost if the pipe was buried at a depth of 180 cm.

8 0
3 years ago
What volume of 0.160 m li2s solution is required to completely react with 130 ml of 0.160 m co no3 2?
Over [174]
The  volume  of  0.160    m   Li2S  solution  required  to  completely  react  with  130 ml  of 0.160  CO(NO3)2  is calculated   as  below

write the  reacting  equation

Co(NO3)2 +  Li2S = 2LiNO3  +  COS

find the    moles  of CO(NO3)2  = molarity  x  volume

=  130 ml  x  0.160=20.8  moles

since the reacting moles between CO(NO3)2  to LiS  is   1:1  the  moles of LiS  is  also  20.8  moles

volume  of Lis  is  therefore =  moles of Lis/ molarity  of LiS

=  20.8/0.160 =  130 Ml
3 0
3 years ago
Adjustment to environmental conditions is known as
alukav5142 [94]

Answer:

A.

Explanation:

Adjust = Adapt if that makes sense.

8 0
3 years ago
Read 2 more answers
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