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pav-90 [236]
3 years ago
7

What is the correct mathematical relationship between the number of moles, the volume, and the standard molar volume of a substa

nce?
Chemistry
2 answers:
masha68 [24]3 years ago
8 0
N=V/Vm

n - the number of moles
V - the volume
Vm=22.4 L/mol - the standard molar volume of gas
zvonat [6]3 years ago
3 0

Answer: {\text {no of moles}}=\frac{\text {Given volume}}{\text {Standard Molar volume}}

Explanation:

According to Avogadro's law, 1 mole of every gas occupies 22.4 L of volume at standard temperature and pressure conditions.

Thus Standard molar volume of substance= 22.4 L

To calculate the moles from mass ,we use the formula:

{\text { no of moles}}=\frac{\text{Given mass}}{\text{Molar mass}}

To calculate the moles from volume ,we use the formula:

Similarly, {\text {no of moles}}=\frac{\text {Given volume}}{\text {Standard Molar volume}}

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In a chemical compound, would you expect an oxide ion to be joined with one atom of calcium or one atom of potassium? Why?
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I know what you're asking but I don't think the question is stated properly. Technically, an atom will not join with an "oxide" ion; i.e., the oxide ion is an atom of oxygen to which two electrons have been added. An oxide ion will add to 2 K ions or 1 Ca ion. The K ion has lost just one electron so it takes two of them to equal the 2- charge on the oxide ion whereas the Ca ion has lost two electrons and it takes only one of them to equal the charge on the oxide ion.

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How many Valance electrons are in an atom of phosphorous
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Answer:

Five

Explanation:

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Based on its electron configuration which element will most likely gain electrons from another element when forming an ionic com
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4 years ago
6. 7. A hyperbaric chamber has a volume of 200. L. (a) How many moles of oxygen are needed to fill the chamber at room temperatu
Otrada [13]

Answer:

a) 24.7 mol

b) 790 g

Explanation:

Step 1: Given data

  • Volume of the chamber (V): 200. L
  • Room temperature (T): 23 °C
  • Pressure of the gas (P): 3.00 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 23°C + 273.15 = 296 K

Step 3: Calculate the moles (n) of oxygen

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol

Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen

The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.

m = n × M

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