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pav-90 [236]
3 years ago
7

What is the correct mathematical relationship between the number of moles, the volume, and the standard molar volume of a substa

nce?
Chemistry
2 answers:
masha68 [24]3 years ago
8 0
N=V/Vm

n - the number of moles
V - the volume
Vm=22.4 L/mol - the standard molar volume of gas
zvonat [6]3 years ago
3 0

Answer: {\text {no of moles}}=\frac{\text {Given volume}}{\text {Standard Molar volume}}

Explanation:

According to Avogadro's law, 1 mole of every gas occupies 22.4 L of volume at standard temperature and pressure conditions.

Thus Standard molar volume of substance= 22.4 L

To calculate the moles from mass ,we use the formula:

{\text { no of moles}}=\frac{\text{Given mass}}{\text{Molar mass}}

To calculate the moles from volume ,we use the formula:

Similarly, {\text {no of moles}}=\frac{\text {Given volume}}{\text {Standard Molar volume}}

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The mass composition of a compound that assists in the coagulation of blood is 76.71% carbon, 7.02% hydrogen, and 16.27% nitroge
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Answer : The empirical of the compound is, C_{11}H_{12}N_2

Explanation :

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 76.71 g

Mass of H = 7.02 g

Mass of N = 16.27 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of N = 14 g/mole

Step 1 : convert given masses into moles.

Moles of C = \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{76.71g}{12g/mole}=6.39moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{7.02g}{1g/mole}=7.02moles

Moles of N = \frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.27g}{14g/mole}=1.16moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{6.39}{1.16}=5.5

For H = \frac{7.02}{1.16}=6.0\approx 6

For N = \frac{1.16}{1.16}=1

The ratio of C : H : N = 5.5 : 6 : 1

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of C : H : N = 11 : 12 : 2

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = C_{11}H_{12}N_2

Therefore, the empirical of the compound is, C_{11}H_{12}N_2

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Tin
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Tin is a chemical element with the symbol Sn and atomic number 50. It is a main group metal in group 14 of the periodic table. Wikipedia
Symbol: Sn
Electron configuration: [Kr] 4d105s25p2
Atomic number: 50
Melting point: 449.5°F (231.9°C)
Atomic mass: 118.71 u
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