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2 years ago

Sound waves that enter the ear canal are directed to the ____, causing it to vibrate.

1 answer:

4 0

According to the research, the correct option the eardrum. Sound waves that enter the ear canal are directed to the <u>eardrum</u>, causing it to vibrate.

<h3>What is the eardrum?</h3>

It is the membrane found in the middle ear of vertebrate animals, separating this sector from the external auditory canal.

When sound waves enter through the external auditory canal, the eardrum vibrates, transmitting its movement to the middle ear through a series of bones and in this way, the pressure change is transformed into a mechanical movement.

Therefore, we can conclude that according to the research, the correct option is the eardrum. Sound waves that enter the ear canal are directed to the <u>eardrum</u>, causing it to vibrate.

Learn more about the eardrum here: brainly.com/question/12770491

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A copper block is removed from a 310C oven and dropped into 1.10kg of water at 23.0C. The water quickly reaches 33.0C and then r

Elis [28]

Answer:

0.432kg or 432g

Explanation:

Copper block is removed from 310C oven.

Mass of water = 1.10kg

Initial temperature of water (θ1) = 23.0C

Final temperature of water (θ2 ) = 33.0C

Specific heat of copper= 385

Specific heat of water = 4190

Let M (copper) be the mass of copper

The amount of heat lost will be absorbed by water

Q (net) = Q(water) + Q(copper) = 0 …………………(1)

Q = MCθ

For water,

Q(water) = M(water) * C(water) * (θ2-θ1)...........(2)

= 1.1 * 4190 * (33.0 -23.0)

= 1.1 *4190 * 10

= 46090J

For copper,

Q(copper) = M(copper) * C(copper) * (33.0 - 310)...........(3)

from equation 1,

Q(copper) = -Q(water)

M(copper) * C(copper) * (33.0 - 310) = - 46090

M(copper) * 385 * (-277) = -46090

M(copper) * 106645 = -46090

M(copper) = -46090 / -106645

M(copper) = 0.432kg

M(copper) = 432g

The mass of copper =432g

7 0

3 years ago

A man 6.00 ft tall approaches a street light 15.0 ft above the ground at the rate of 4.00 ft/s. How fast is the end of the man

klio [65]

Answer:

$\frac{dx}{dt} = 10 ft/s$

Explanation:

As per given figure let say the tip of the shadow is at distance "x" from the base of the lamp

so here we have

$\frac{x}{15} = \frac{x - y}{6}$

so we have

$6x = 15 x - 15 y$

$15 y = 9 x$

now we have

$5\frac{dy}{dt} = 2\frac{dx}{dt}$

$5(4) = 2\frac{dx}{dt}$

$\frac{dx}{dt} = 10 ft/s$

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4 years ago

Calculate the average speed of a snake that moves 700 meters in 5 hours?

ddd [48]

140 ? i’m guessing there doesn’t look like there’s much to the question

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4 years ago

Read 2 more answers

One small speaker is placed 3m to the east of a second speaker, and a listener stands 4m directly south of one of the speakers.

alexandr402 [8]

Answer:

The value is $\lambda = 2 \ m$

Explanation:

From the question we are told that

The distance of the speaker from the second speaker to the east is $d = 3 \ m$

The distance of the speaker from the listener to the south is $a = 4 \ m$

Generally given that if the speaker move in any direction, their sound become louder , it then mean that the position of the listener of minimum sound (i.e a position of minima ) ,

Generally the path difference of the sound produce by both speaker at a position of minima is mathematically represented as

$y = \frac{\lambda}{2}$

Generally considering the orientation of the speakers and applying Pythagoras theorem we see that distance from the second speaker to the listener is mathematically represented as

$b = \sqrt{d^ 2 + a^2 }$