Answer:
3.41 s
114 m
Explanation:
The object is falling in free fall, accelerated by the surface gravity of Earth. We can use the equation for position under constant acceleration:
X(t) = X0 + V0 * t + 1/2 * a * t^2
We set up a frame of reference with the origin at the point the object was released and the X axis pointing down. Then X0 = 0. Since the problem doesnt mention an initial speed we assume V0 = 0.
It travels 0.5h in the last 1 second of the fall. This means it also traveled in the rest of the time of the fall. t = t1 is the moment when it traveled 0.5*h.
0.5*h = 1/2 * a * t1^2
h = a * t1^2
It travels 0.5*h in 1 second.
h = X(t1 + 1) = 1/2 * a * (t1+1)^2
Equating both equations:
a * t1^2 = 1/2 * a * (t1+1)^2
We simplify a and expand the square
t1^2 = 1/2 * (t1^2 + 2*t1 + 1)
t1^2 - 1/2 * t1^2 - t1 - 1/2 = 0
1/2 * t1^2 - t1 - 1/2 = 0
Solving electronically:
t1 = 2.41 s
total time = t1 + 1 = 3.41.
Now
h = a * t1^2
h = 9.81 * 3.41^2 = 114 m
Answer:
Hey mate.....
Explanation:
This is ur answer....
<em>A human has 4 types of teeth:-</em>
<em>--> 8 Incisors.
</em>
<em>--> 4 Canines.
</em>
<em>--> 8 Premolars.
</em>
<em>--> 12 Molars (including 4 wisdom teeth)</em>
<em></em>
Hope it helps!
Mark me brainliest....
FOLLOW ME! :)
<span>10. what part of the experiment was food? C. CONSTANT
11. What part of experiment was the heartbeat? B. DEPENDENT VARIABLE
12. what part of experiment was the h2o temp.? C. CONSTANT
13. what part of the experiment was pop..2? D. CONTROL
14. what part of experiment was caffeine? A. INDEPENDENT VARIABLE
Constant are those items that have been applied consistently w/o change.
Dependent variable are variables that change due to the application of independent variable.
Control is the basis of the experiment. It is what the result of the experiment is compared to, to check whether there are changes or not.</span>
This is true. they have numbers on the side that help to determine the volume.
Answer: 2,464m
Explanation:
Echo made by a source is dependent on the velocity of the sound in air/water, the distance between the source and the reflector and the time taken
Using the echo formula
2x = vt
Where x is the distance between the source and the reflector
v is the velocity of the sound in sea water is approximately= 1540m/s (This varies from place to place and depending on the season and nature of water)
t is the time taken
t = 3.20s
Substituting this datas into the equation to get 'x'
2x = 1540 × 3.20
x = 1540×3.20/2
x = 2,464m
The distance between the object creating the echo is 2,464m