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notsponge [240]
2 years ago
15

What advanced safety features are now standard on 2023 Z?

Engineering
1 answer:
Anettt [7]2 years ago
3 0

The advanced safety features that are now standard on 2023 Z are:

  • Pedestrian Detection and Automatic Emergency Braking
  • Intelligent Forward Collision Warning (IFCW).
  • Blind Spot Alert.

<h3>What is 2023 Z?</h3>

The above is the short name or nickname for the All New 2023 Nissan Z coupe Sports car.

The care also features Advanced driver assist and safety technology which relieves the driver's everyday workload, allowing you to focus on what matters most.

Learn more about safety features in cars:
brainly.com/question/24078882
#SPJ1


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The annual average of solar photovoltaic energy in Phoenix is 6,720
Dovator [93]

Answer:

The amount of money saved is $22,075.2

Explanation:

The solar voltaic energy in Phoenix, S_E = 6,720 Wh/m²/day

The area on the roof available for solar panels, A = 500 m²

The percentage of the energy received by the solar panels converted into electricity, η = 15% = 0.15

The cost of electricity, C = $0.12/kWh

The number of days in a year, t = 365 days

Therefore, the maximum area covered by the solar panel = A = 500 m²

The total solar photovoltaic energy received by the solar panels, 'E', in a year is given as follows;

E = S_E × A × t

By plugging in the values of the variables, we get;

E = 6,720 Wh/m²/day × 500 m² × 365 days = 1,226,400,000 Wh

The electrical energy generated, E_e = η × E

∴ E_e = 0.15 × 1,226,400,000 Wh = 183960000 Wh = 183,960 kWh

The amount of money saved = The cost of electricity generated = C × E_e

C × E_e = $0.12/kWh × 183,960 kWh = $22,075.2

∴ The amount of money saved = C × E_e = $22,075.2

3 0
2 years ago
Consider uniaxial extension of a test specimen. It has gauge length L = 22 cm (the distance between where it is clamped in the t
Katena32 [7]

Answer:

A) 4800.6 N

B) 0.2255 mm/min

C) 8.6792 inches

Explanation:

Given data :

gauge Length = 22 cm = 220 mm

cross section diameter/thickness = 1.8 mm

young's modulus ( E ) = 205 GPa

Ultimate tensile strength ( σu ) = 420MPa

Time = 2 mins

A) what force would fracture the specimen

σU = Ff /A

where A (area) = thickness * width ( unknown )  hence we assume a width of 6.35 mm

Ff = σU × A =  420 * 1.8 * 6.35 = 4800.6 N

B) calculate the strain rate

Ultimate tensile strength ( σU ) = εE

ε = σU / E = 420/205000 = 0.00205

also  ε ​​​​​​ =  ΔL / Li = ( Lf - Li) / Li = (Lf / Li) - 1

 therefore  ε ​​​​​​ + 1 = (Lf / Li) = 1 + 0.00205 = 1.00205

 Li = gauge length = 220 mm

Hence :  Lf = 1.00205 × gauge length =  1.00205 * 220 =  220.451 mm

  strain rate

(Lf - Li) / Time = (0.451) / 2 min = 0.2255 mm/min

C) Elongation in inches prior to fracture

ΔL = ε × Li = 0.451 mm

Lf = 220 mm + 0.451 mm = 220.451 mm =  8.6792 inches

3 0
3 years ago
What is EL Niño?
postnew [5]

Answer:

B

Explanation:

This occurs over the Pacific Ocean, so C and D are already wrong. El Nino heats the water and not cools it, so A is incorrect. So commonsense says that the answer is B.

4 0
3 years ago
How should employees talk to clients)
s344n2d4d5 [400]

Answer:

Explanation:

Respectfully and calmly

3 0
3 years ago
Calculate the tensile modulus of elasticity for a laminated composite consisting of 62 percent by volume of unidirectional carbo
kompoz [17]

Answer:

4.30 gp

Explanation:

''.''

5 0
3 years ago
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