Answer:
particles of a solid object packed together
Answer:
beam with a span length of 10 ft, a width of 8 in, and an effective depth of 20 in. Normal weight concrete is used for the beam. This beam carries a total factored load of 9.4 kips. The beam is reinforced with tensile steel, which continues uninterrupted into the support. The concrete has a strength of 4000 psi, and the yield strength of the steel is 60,000 psi. Using No. 3 bars and 60,000 psi steel for stirrups, do the followings:
Answer:
![Hr=4.2*10^7\ btu/hr](https://tex.z-dn.net/?f=Hr%3D4.2%2A10%5E7%5C%20btu%2Fhr)
Explanation:
From the question we are told that:
Water flow Rate ![R=4.5slug/s=144.78ib/sec](https://tex.z-dn.net/?f=R%3D4.5slug%2Fs%3D144.78ib%2Fsec)
Initial Temperature ![T_1=60 \textdegree F](https://tex.z-dn.net/?f=T_1%3D60%20%5Ctextdegree%20F)
Final Temperature ![T_2=140 \textdegree F](https://tex.z-dn.net/?f=T_2%3D140%20%5Ctextdegree%20F)
Let
Specific heat of water ![\gamma= 1](https://tex.z-dn.net/?f=%5Cgamma%3D%201)
And
![\triangle T= 140-60](https://tex.z-dn.net/?f=%5Ctriangle%20T%3D%20140-60)
![\triangle T= 80\ Deg.F](https://tex.z-dn.net/?f=%5Ctriangle%20T%3D%2080%5C%20Deg.F)
Generally the equation for Heat transfer rate of water
is mathematically given by
Heat transfer rate to water= mass flow rate* specific heat* change in temperature
![H_r=R* \gamma*\triangle T](https://tex.z-dn.net/?f=H_r%3DR%2A%20%5Cgamma%2A%5Ctriangle%20T)
![H_r=144.78*80*1](https://tex.z-dn.net/?f=H_r%3D144.78%2A80%2A1)
![H_r=11582.4\ btu/sec](https://tex.z-dn.net/?f=H_r%3D11582.4%5C%20btu%2Fsec)
Therefore
![H_r=11582.4\ btu/sec*3600](https://tex.z-dn.net/?f=H_r%3D11582.4%5C%20btu%2Fsec%2A3600)
![Hr=4.2*10^7\ btu/hr](https://tex.z-dn.net/?f=Hr%3D4.2%2A10%5E7%5C%20%20btu%2Fhr)
Answer:
a)We know that acceleration a=dv/dt
So dv/dt=kt^2
dv=kt^2dt
Integrating we get
v(t)=kt^3/3+C
Puttin t=0
-8=C
Putting t=2
8=8k/3-8
k=48/8
k=6