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Ket [755]
4 years ago
9

What is the resistance of a 4.2 m length of copper wire 1.9 mm in diameter? Express your answer to two significant figures and i

nclude the appropriate units.

Physics
2 answers:
anzhelika [568]4 years ago
6 0

Explanation:

Below is an attachment containing the solution

Nina [5.8K]4 years ago
5 0

Answer:

The resistance is 0.02484 Ω

Explanation:

we have the following data:

L = length = 4.2 m

D = diameter = 1.9 mm = 0.0019 m

p = the resistivity of copper = 1.68x10^-8 Ω*m

we calculate the area:

A = pi*r^2 = pi*(0.0019 m/2)^2 = 2.84x10^-6 m

resistance is given by:

R = (p*L)/A = ((1.68x10^-8 Ω*m)*(4.2))/2.84x10^-6 m = 0.02484 Ω

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inna [77]

Answer:

4.00m

Explanation:

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4 0
4 years ago
Enter the expression 2gΔym−−−−−√, where Δ is the uppercase Greek letter Delta.
Anon25 [30]
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5 0
3 years ago
You have a nightlight plugged into an outlet in the hallway, which uses 3.5 watts when plugged in. If the house circuit provides
nekit [7.7K]
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7 0
3 years ago
Read 2 more answers
A 0.280-kg volleyball approaches a player horizontally with a speed of 15.0 m/s. The player strikes the ball with her fist and c
Genrish500 [490]

Answer:

Impulse = 10.36 kg m/s

average force = 172.667 N

Explanation:

given data

mass = 0.280 kg

speed = 15.0 m/s

speed = 22.0 m/s

to find out

impulse and magnitude of the average force

solution

we know that Impulse is change in momentum that is

initial momentum = mass × speed    ..........1

initial momentum = 0.28 × (15)

initial momentum = 4.2 kg m/s

Final momentum = mass × speed     ..........2

Final momentum = 0.28 × (-22)

Final momentum = -6.16 kg m/s

so now we get Impulse that is

Impulse = 4.2 - (-6.16)

Impulse = 10.36 kg m/s

and

average force will be

average force = impulse ÷ time

average force = \frac{10.36}{0.060}

average force = 172.667 N

6 0
3 years ago
An Arrow (0.5 kg) travels with velocity 60 m/s to the right when it pierces an apple (1 kg) which is initially at rest. After th
Rom4ik [11]

Answer:

Velocity after collision will be 20 m/sec

Explanation:

We have given mass of arrow m_1=0.5kg

Mass of arrow v_1=60m/sec

Mass of apple m_2=1kg

Apple is at rest so velocity of apple v_2=0m/sec

According to conservation of momentum

Momentum before collision is equal to momentum after collision

m_1v_1+m_2v_2=(m_1+m_2)v

0.5\times 60+1\times 0=(0.5+1)v

1.5v=30

v = 20 m/sec

5 0
3 years ago
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