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3 years ago

If a bar magnet's neutral region is broken into tow, what will mist likely occur

2 answers:

7 0

<span>The answer is C. The north post of one magnet pulls in the south shaft of a moment magnet, while the north shaft of one magnet repulses the other magnet's north shaft. So we have the normal saying: like shafts repulse, dissimilar to posts draw in. A magnet makes an undetectable region of attraction surrounding it called an attractive field.</span>

Korolek [52]3 years ago

7 0

Assuming that the division of the magnet was gentle in nature, so as to not disturb the alignment of the domains, the answer is B. each of the two segments of the original bar magnet will have a north and a south pole<span>. This is due to the fact that a magnet is essentially filled with bundles of magnetic domains, each having its north pole facing towards the magnet's north pole and its south pole facing the magnet's south pole. Therefore, cutting gently will only expose the poles from the middle of the magnet.</span>

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Calculate the masses of oxygen and nitrogen that are dissolved in of aqueous solution in equilibrium with air at 25 °C and 760 T

shtirl [24]

Explanation:

Let us assume that the volume of given aqueous solution is 7.5 L.

Therefore, according to Henry's law, the relation between concentration and pressure is as follows.

C = $\frac{P}{K_{h}}$

where, pressure (P) = 760 torr = 1 atm

According to Henry's law, constants for gases in water at $25^{o}C$ are as follows.

$p(O_{2})$ = 0.21 atm = 0.21 bar

$p(N_{2})$ = 0.78 atm = 0.78 bar

$K_{h}$ for $O_{2}$ = $7.9 \times 10^{2} bar/mol$

$K_{h}$ for $N_{2}$ = $1.6 \times 10^{3} bar /mol$

Since, 21% oxygen is present in air so, its mass will be 0.21 g. Similarly, 78% nitrogen means the mass of nitrogen is 0.78 g.

Therefore, concebtrations will be calculated as follows.

$C(O_{2}) = \frac{0.21}{7.9 \times 10^{2}} = 2.66 \times 10^-4 mol/L$

$C(N_2) = \frac{0.78}{1.6 \times 10^3} = 4.875 \times 10^-4 mol/L$

Now, we will calculate the number of moles as follows.

$n(O_{2}) = 7.5 \times 2.66 \times 10^-4 = 1.995 \times 10^-3$ mol

$n(N_2) = 7.5 \times 4.875 \times 10^-4 = 3.66 \times 10^-3$ mol

As the molar mass of $O_2$ = 32 g/mol

Hence, mass of oxygen will be as follows.

Mass of $O_2 = 32 \times 1.995 \times 10^-3 \times 1000$

= 63.84 mg

As the molar mass of $N_{2}$ = 28

Mass of $N_{2} = 28 \times 3.66 \times 10^-3$ = 102.5 mg

Thus, we can conclude that mass of oxygen is 63.84 mg and nitrogen is 102.5 mg.

5 0

4 years ago

Read 2 more answers

Reason why chemistry is studied

mina [271]

Answer: Chemistry is the study of change. Various reasons why to study Chemistry is to appreciate the fundamentals of the world such as the composition of all living thing. We are made up of matter. The interaction of sub atomic particles in an atom to form a single being. Also to understand how certain chemicals are beneficial and harmful in our lives just by reading product labels.

Explanation:

3 0

3 years ago

What are atoms?

user100 [1]

Answer:

The smallest particle of a chemical element can be defined as an atom.

Explanation:

The number of protons in one atom of an element determines the atom's identity, and the number of electrons determines its electrical charge.

a single electron or one of two or more electrons in the outer shell of an atom that is responsible for the chemical properties of the atom is known as valence electrons.

An atom's reactivity is its tendency to lose or gain electrons. ... This is because they have one outer electron and losing it gives them the stability of a outer electron shell as the next level... The reactivities of elements can be predicted by periodic trends.

7 0

3 years ago

Read 2 more answers

Below is the Lewis structure of the hydrogen cyanide molecule.

lianna [129]

Answer :

The number of bonding pairs of electrons around the hydrogen atom = 2

The number of lone pairs of electrons around the hydrogen atom = 0

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $HCN$

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electrons and nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in $HCN$ = 1 + 4 + 5 = 10

According to Lewis-dot structure we conclude that, there are 8 number of bonding electrons and 2 number of non-bonding electrons.

The number of bonding pairs of electrons around the hydrogen atom = 2

The number of lone pairs of electrons around the hydrogen atom = 0

8 0

3 years ago

Compare and contrast physical property and chemical property

amm1812

Physical properties are properties that change form but not it's chemical compound

chemical properties are properties that change in chemical substance like burning tearing

3 0

3 years ago