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Semenov [28]
3 years ago
9

If a bar magnet's neutral region is broken into tow, what will mist likely occur

Chemistry
2 answers:
ololo11 [35]3 years ago
7 0
<span>The answer is C. The north post of one magnet pulls in the south shaft of a moment magnet, while the north shaft of one magnet repulses the other magnet's north shaft. So we have the normal saying: like shafts repulse, dissimilar to posts draw in. A magnet makes an undetectable region of attraction surrounding it called an attractive field.</span>
Korolek [52]3 years ago
7 0
Assuming that the division of the magnet was gentle in nature, so as to not disturb the alignment of the domains, the answer is B. each of the two segments of the original bar magnet will have a north and a south pole<span>. This is due to the fact that a magnet is essentially filled with bundles of magnetic domains, each having its north pole facing towards the magnet's north pole and its south pole facing the magnet's south pole. Therefore, cutting gently will only expose the poles from the middle of the magnet.</span>
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Answer:

Potential energy

Explanation:

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3 years ago
Read 2 more answers
Consider the following intermediate reactions.
Alja [10]

2.1648 kg of CH4 will generate 119341 KJ of energy.

Explanation:

Write down the values given in the question

CH4(g) +2 O2 → CO2(g) +2 H20 (g)

ΔH1 = - 802 kJ

2 H2O(g)→2 H2O(I)

ΔH2= -88 kJ

The overall chemical reaction is

CH4 (g)+2 O2(g)→CO2(g)+2 H2O (I) ΔH2= -890 kJ

CH4 +2 O2 → CO2 +2 H20

(1mol)+(2mol)→(1mol+2mol)

Methane (CH4) = 16 gm/mol

oxygen (O2) =32 gm/mol

Here 1 mol CH4 ang 2mol of O2 gives 1mol of CO2 and 2 mol of 2 H2O

which generate 882 KJ /mol

Therefore to produce 119341 KJ of energy

119341/882 = 135.3 mol

to produce 119341 KJ of energy, 135.3 mol of CH4 and 270.6 mol of O2 will require

=135.3 *16

=2164.8 gm

=2.1648 kg of CH4

2.1648 kg of CH4 will generate 119341 KJ of energy

4 0
3 years ago
Read 2 more answers
A compound is 2% H, 32.7% S, and 65.3% O by mass. What is the subscript on the O in the empirical formula for this compound?
IceJOKER [234]
Since all of those percents add up to 100, you can just directly convert that to grams. So now you can use 2 grams H, 32.7 grams S, and 65.3 grams O. Use that info and convert that to moles for an answer of 2mol H, 1mol S, and 4mol O. In every empirical question you need to divide each quantity of moles by the lowest number. In this case, that number is one, so they stay the same, but it's important to remember that step. You're final chemical formula would be H2SO4 and the answer to your question would be that the subscript for oxygen is 4. Hope this helped! 
4 0
3 years ago
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