Answer: FR=2.330kN
Explanation:
Write down x and y components.
Fx= FSin30°
Fy= FCos30°
Choose the forces acting up and right as positive.
∑(FR) =∑(Fx )
(FR) x= 5-Fsin30°= 5-0.5F
(FR) y= Fcos30°-4= 0.8660-F
Use Pythagoras theorem
F2R= √F2-11.93F+41
Differentiate both sides
2FRdFR/dF= 2F- 11.93
Set dFR/dF to 0
2F= 11.93
F= 5.964kN
Substitute value back into FR
FR= √F2(F square) - 11.93F + 41
FR=√(5.964)(5.964)-11.93(5.964)+41
FR= 2.330kN
The minimum force is 2.330kN
Let say the height of two balls from the ground is H
now we can use kinematics

now we have


now in the same time ball on the left will cover the horizontal distance between them
![v_x = \frac{d}{ t}[/tex[tex]v_x = \frac{3}{\sqrt{\frac{2H}{g}}}](https://tex.z-dn.net/?f=v_x%20%3D%20%5Cfrac%7Bd%7D%7B%20t%7D%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5Dv_x%20%3D%20%5Cfrac%7B3%7D%7B%5Csqrt%7B%5Cfrac%7B2H%7D%7Bg%7D%7D%7D)
<em>so above is the horizontal speed of the left ball</em>
Answer:
Explanation:
Ne has its outside shell full of electrons; therefore, its reaction with other elements is minimal if at all. Na, the next element, has 1 more proton and 1 more electron. More importantly that added electron is in the outside shell. It can fill that shell by ADDing 7 more electrons or LOSing the one electron. Obviously, it loses the one electron and it does so with gusto which makes Na a very reaction element while Ne is not reactive at all. Now follow oobleck's instructions, add what you read to what I've written,then summarize all of it in your own words.