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Sidana [21]
2 years ago
6

Explain how an object moving at a constant speed can have a nonzero acceleration

Physics
2 answers:
SOVA2 [1]2 years ago
8 0
Its very simple if a body is moving in circle the magnitude of its velocity remain constant  but its direction changes because velocity is directed towards tangent and at every point in a cirlce its direction will be different (along tangent) so velocity is not uniform .As acceleration is the rate  change of velocity  so it will be non zero because velocity is changing due to its direction.
laila [671]2 years ago
8 0

Acceleration depends on the change in an object’s velocity. An object moving at a constant speed can experience a nonzero acceleration if the direction of the object’s motion changes.

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If the work done to stretch an ideal spring by 4.0 cm is 6.0 j, what is the spring constant (force constant) of this spring?
Alisiya [41]

Answer:

The spring constant is 3750 N/m  

Explanation:

Use the following two relationships:

(Work) = (Force) x (Displacement)

(Force) = (Spring constant) x (Displacement)

=>

(Spring constant) = (Force) / (Displacement) = (Work) / (Displacement)^2

(Spring constant) = 6.0 kg.(m^2/s^2) / 0.0016 m^2 = 3750 N/m

The spring constant is 3750 N/m  

4 0
3 years ago
Explain how do winds cause surface currents?
igor_vitrenko [27]

Answer:

As wind or an ocean current moves, the Earth spins underneath it. ... The Coriolis effect bends the direction of surface currents to the right in the Northern Hemisphere and left in the Southern Hemisphere.

Explanation:

The Coriolis effect causes winds and currents to form circular patterns.

8 0
3 years ago
The wheel of a stationary exercise bicycle at your gym makes one rotation in 0.670 s. Consider two points on this wheel: Point P
defon

Answer:

0.938 m/s.

Explanation:

Given:

ω = 1 rev in 0.67 s

In rad/s,

1 rev = 2pi rad

ω = 2pi ÷ 0.67

= 9.38 rad/s

Rp = 10 cm

= 0.1 m

V = ω × r

= 9.38 × 0.1

= 0.938 m/s.

5 0
3 years ago
Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 9.50 cm apart. You see an object jump from sid
Serhud [2]

Answer: 12.67 cm, 8 cm

Explanation:

Given

Normal distance of separation of eyes, d(n) = 6 cm

Distance of separation is your eyes, d(y) = 9.5 cm

Angle created during the jump, θ = 0.75°

To solve this, we use the formula,

θ = d/r, where

θ = angle created during the jump

d = separation between the eyes

r = distance from the object

θ = d/r

0.75 = 9.5 / r

r = 9.5 / 0.75

r = 12.67 cm

θ = d/r

0.75 = 6 / r

r = 6 / 0.75

r = 8 cm

Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye

8 0
3 years ago
Is god real??? i wanna know
NemiM [27]
In my opinion, yes the bible tell us that "For God so loved<span> the world that he gave</span><span> his one and only Son,</span><span> that whoever believes</span><span> in him shall not perish but have eternal life" 
So my answer is yes</span>
6 0
3 years ago
Read 2 more answers
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