Answer:
Explanation:
Average energy contained by a slice of pizza is 860 J .
energy used in lifting 32 kg bar by .50 m = mgh
= 32 x 9.8 x .5 = 156.8 J
efficiency is 25 % , so energy used up = .75 x 156.8 = 117.6 J
So number of times exercise to be repeated to burn off energy of a slice of pizza
= 860 / 117.6
= 7.3 or 7 times .
You would divide the meters by the seconds so the answer would be A 9m/s
Answer:
v = 0.999981c m/s
Explanation:
Using the time dilation equation
T = stationary time = 100 years
T₀ = 11/12 years = 0.917 years
v = speed of travel in the space = ?
c = speed of light = 3 * 10⁸ m/s
v = 299987395.57 m/s
v = 2.99 * 10⁸ m/s
v = 0.999981c m/s
When you sketch the problem, it would look like that shown in the picture. The velocity the airplane should achieve must be 120 km/h in order for it to lift off the ground and take-off. Before this, it has to build up speed in order to reach the final velocity from rest. In rectilinear motion, one of the useful equations used is
2ax = vf² - vi²
For consistency, let's convert km/h to m/s.
120 km/h * (1000 m/1 km) * (1 h/3600 s) = 33.33 m/s
Substituting the values,
2a(280 m) = (33.33 m/s)² - 0²
a = 1.984 m/s
The minimum acceleration is 1.984 m/s.
(a) The work done by the force applied by the tractor is 79,968.47 J.
(b) The work done by the frictional force on the tractor is 55,977.93 J.
(c) The total work done by all the forces is 23,990.54 J.
<h3>
Work done by the applied force</h3>
The work done by the force applied by the tractor is calculated as follows;
W = Fd cosθ
W = (5000 x 20) x cos(36.9)
W = 79,968.47 J
<h3>Work done by frictional force</h3>
W = Ffd cosθ
W = (3500 x 20) x cos(36.9)
W = 55,977.93 J
<h3>Net work done by all the forces on the tractor</h3>
W(net) = work done by applied force - work done by friction force
W(net) = 79,968.47 J - 55,977.93 J
W(net) = 23,990.54 J
Learn more about work done here: brainly.com/question/25573309
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