Answer:The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound, C5H10O2, exhibits strong, broad absorption across the 2500-3200 cm^1 region and an intense absorption at 1715 cm'^-1. Relative absorption intensity: (s)=strong, (m)-medium, (w) weak. What functional class(cs) docs the compound belong to List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm^1. The functional class(es) of thla compound is(are) alkane (List only if no other functional class applies.) alkene terminal alkyne internal alkyne arene alcohol ether amine aldehyde or ketone carboxylic acid ester nitr
Answer:
a) O²⁻ + H₂O <-----> OH⁻ + OH⁻
Acid = H₂O
Base = O²⁻
Conjugate Acid = OH⁻
Conjugate Base = OH⁻
b) HClO₄ + H₂SO₄ <-----> ClO₄⁻ + H₃SO₄⁺
Acid = HClO₄
Base = H₂SO₄
Conjugate Acid = H₃SO₄⁺
Conjugate Base = ClO₄⁻
c) NH₃ + HNO₃ <--> NH4⁺ + NO₃⁻
Acid = HNO₃
Base = NH₃
Conjugate Acid = NH4⁺
Conjugate Base = NO₃⁻
Explanation:
- Acids are molecules or ions capable of donating a proton (H⁺).
- Bases are molecules or ions that readily accept the H⁺ from acids.
- Conjugate Acids, according to the Brønsted–Lowry acid–base theory, are chemical compounds formed after the reception of a proton (H⁺) from an acid by a base.
- Conjugate Bases, Brønsted–Lowry acid–base theory, are the leftovers from when acids donate their proton (H⁺).
PV=nRT
P = 85.0 x 10^3 Pa
T = 273 + 20 = 293 K
n = 2.0 moles
R = 8.314 m3. pa / mol .K
V = 2.0 x 293 x 8.314 / 85.0x10^3 = 0.195623529 m^3
Answer:
starts form from a accumulation of gas and dust ,which collapses due to gravity and starts to form stars
