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serious [3.7K]
3 years ago
9

Bambi is walking along the train tracks when he suddenly notices a fast approaching train and freezes in his tracks like a deer

in headlights. IF the 1000kg train collides with Bambi at a speed of 8 m/s, and Bambi, who weighs 75kg, gets stuck to the front of the train, how fast will the train and Bambi continue to move after the collision
Physics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

The final speed of the train and Bambi after collision is 7.44 m/s

Explanation:

Given;

mass of the train, m₁ = 1000kg

mass of  Bambi, m₂ = 75kg

initial speed of the train, u₁ =  8 m/s

initial speed of Bambi, u₂ =  0 m/s

If Bambi gets stuck to the front of the train, then the collision is inelastic.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

v is the final speed of the train and Bambi after collision

Substitute the given values and solve for v

1000 x 8 + 75 x 0 = v (1000 + 75)

8000 = v (1075)

v = 8000/1075

v = 7.44 m/s

Therefore, the final speed of the train and Bambi after collision is 7.44 m/s

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How do scientists know the continents were once closer than they are today? Explain your answer in 2-3 complete sentences.
WITCHER [35]

Answer:

Continental drift describes one of the earliest ways geologists thought continents moved over time. Today, the theory of continental drift has been replaced by the science of plate tectonics. 

 

The theory of continental drift is most associated with the scientist Alfred Wegener. In the early 20th century, Wegener published a paper explaining his theory that the continental landmasses were “drifting” across the Earth, sometimes plowing through oceans and into each other. He called this movement continental drift. 

6 0
2 years ago
9. What is the gravitational potential energy of a 61.2 kg person standing on the roof of a 10-storey building? (Each storey is
kow [346]

Answer:

15009

Explanation:

PE = mgh

PE = 61.2(9.81)(10 * 2.50)

PE = 15009.3

3 0
2 years ago
An archer puts a 0.30-kg arrow to the bowstring. An average force of 201 N is exerted to draw the string back 1.3 m. Assuming th
vovikov84 [41]

Answer:

41.74 m/s

Explanation:

The energy used to draw the bowstring = the kinetic energy of the arrow.

Fd = 1/2mv²................................ Equation 1

Where F = force, d = distance move string, m = mass of the arrow, v = speed of the arrow.

make v the subject of the equation

v = √(2Fd/m)...................... Equation 2

Given: F = 201 N, m = 0.3 kg, d = 1.3 m.

Substitute into equation 2

v = √(2×201×1.3/0.3)

v = √(1742)

v = 41.74 m/s.

Hence the arrow leave the bow with a speed of 41.74 m/s

3 0
3 years ago
Read 2 more answers
In a race, Usain Bolt accelerates at
jeka94

Answer:

65.87 s

Explanation:

For the first time,

Applying

v² = u²+2as.............. Equation 1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance

From the question,

Given:  u = 0 m/s (from rest), a = 1.99 m/s², s = 60 m

Substitute these values into equation 1

v² = 0²+2(1.99)(60)

v² = 238.8

v = √238.8

v = 15.45 m/s

Therefore, time taken for the first 60 m is

t = (v-u)/a............ Equation 2

t = (15.45-0)/1.99

t = 7.77 s

For the final 40 meter,

t = (v-u)/a

Given: v = 0 m/s(decelerates), u = 15.45 m/s, a = -0.266 m/s²

Substitute into the equation above

t = (0-15.45)/-0.266

t = 58.1 seconds

Hence total time taken to cover the distance

T = 7.77+58.1

T = 65.87 s

3 0
3 years ago
A long copper wire of radius 0.321 mm has a linear charge density of 0.100 μC/m. Find the electric field at a point 5.00 cm from
krek1111 [17]

Answer:

E=35921.96N/C

Explanation:

From the question we are told that:

Radius r=0.321mm

Charge Density \mu=0.100

Distance d= 5.00 cm

Generally the equation for electric field is mathematically given by

E=\frac{mu}{2\pi E_0r}

E=\frac{0.100*10^{-6}}{2*3.142*8.86*10^{-12}*5*10^{-2}}

E=35921.96N/C

4 0
3 years ago
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