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zhenek [66]
3 years ago
6

Two fishing boats depart a harbor at the same time, one traveling east, the other south. the eastbound boat travels at a speed 1

mi/h faster than the southbound boat. after 5 h the boats are 25 mi apart. find the speed of the southbound boat.
Physics
1 answer:
Novosadov [1.4K]3 years ago
6 0
<span>they are travelling at right angles to each other.
 At any given instant they form a right triangle with their starting point
 </span>South bound <span>= x  [mi/h]
</span> East bound <span> = x+1 [mi/h]
 after five hours they will be
 d=5x
 and
 d=5(x+1)
 miles away from the starting point 
 (5x)^2+(5(x+1))^2=625
 25x^2+(5x+5)^2=625
 25x^2+25x^2+50x+25=625
 50</span>x^2+50x-600=0
<span> x^2+ x - 12=0
 (x+4)(x-3)=0
 take the postive value
 x= 3 mph the speed of south bound
 4mph east bound </span>
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