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Lelu [443]
3 years ago
11

In which of the following is the number of neutrons correctly represented? A. fluorine: atomic number 9, mass 19, neutrons 0 B.

arsenic: atomic number 33, mass 75, neutrons 108 C. magnesium: atomic number 12, mass 24, neutrons 24 D. uranium: atomic number 92, mass 238, neutrons 146
Chemistry
2 answers:
Digiron [165]3 years ago
4 0
D. uranium: atomic number 92, mass 238, neutrons 146

238-92=146
earnstyle [38]3 years ago
3 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Atomic number is defined as the number of protons that are present in an atom. It is represented as Z.

Z = Atomic number = Number of protons

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.  It is represented as A.

A = Mass number = Number of protons + Number of neutrons

For the given options:

  • <u>Option A:</u> Fluorine

Atomic number = 9

Mass number = 19

Number of neutrons = 19 - 9 = 10

Thus, the number of neutrons are not represented correctly.

  • <u>Option B:</u> Arsenic

Atomic number = 33

Mass number = 75

Number of neutrons = 75 - 33 = 42

Thus, the number of neutrons are not represented correctly.

  • <u>Option C:</u> Magnesium

Atomic number = 12

Mass number = 24

Number of neutrons = 24 - 12 = 12

Thus, the number of neutrons are not represented correctly.

  • <u>Option D:</u> Uranium

Atomic number = 92

Mass number = 238

Number of neutrons = 238 - 92 = 146

Thus, the number of neutrons are represented correctly.

Hence, the correct answer is Option D.

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Answer:

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Explanation:

Hello!

In this case, since the net ionic equation of a chemical reaction shows up the ionic species that result from the simplification of the spectator ions, which are those at both reactants and products sides, we take into account that aqueous species ionize into ions whereas liquid, solid and gas species remain unionized. In such a way, for the reaction of cesium phosphate and silver nitrate we can write the complete molecular equation:

Cs_3PO_4(aq)+3AgNO_3(aq)\rightarrow Ag_3PO_4(s)+3CsNO_3(aq)

Whereas the three aqueous salts are ionized in order to write the following complete ionic equation:

3Cs^+(aq)+PO_4^{3-}(aq)+3Ag^+(aq)+3NO_3^-(aq)\rightarrow Ag_3PO_4(s)+3Cs^+(aq)+3NO_3^-(aq)

In such a way, since the cesium and nitrate ions are the spectator ions because of the aforementioned, the net ionic equation turns out:

PO_4^{3-}(aq)+3Ag^+(aq)\rightarrow Ag_3PO_4(s)

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