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mr Goodwill [35]
3 years ago
10

Somethings wrong with Tommy’s left eye. You have to examine it very carefully. Can you bring the parts of the eye in the correct

order, from outside to inside?

Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
3 0

Answer:

cornea - Iris - lens - retina.( From outside to inside)

Explanation:

The correct order from outside to inside is cornea - Iris - lens - retina.

The cornea is the front part of the eye. It helps the eye to focus on light. It is transparent.

The Iris is located at the back of the cornea.The quantity of light that falls on the eye is determined by the Iris. The Iris is colored.

Lens allows light to be focused on the retina. It is behind the Iris.

The retina is the part of the eye that senses light. The retina sends the light signal it senses to the brain for interpretation. It is the innermost if all the options given.

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The complete combustion of propane (C3H8) in the presence of oxygen yields CO2 and H2O: C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (g) a
mixas84 [53]

Answer:

26.9 L is the volume of CO₂, we obtained

Explanation:

The reaction is: C₃H₈(g) + 5O₂(g)  →  3CO₂ (g) + 4H₂O (g)

Let's determine the reactants moles:

27.5 g . 1mol / 44 g = 0.625 moles

We need density of O₂ to determine mass and then, the moles.

O₂ density = O₂ mass / O₂ volume

O₂ density . O₂ volume = O₂ mass

1.429 g/L . 45L = O₂ mass → 64.3 g

Moles of O₂ → 64.3 g . 1mol/32g = 2.009 moles

Let's find out the limiting reactant:

1 mol of propane needs 5 moles of oxygen to react

Then, 0.625 moles will react with (0.625 . 5)/1 = 3.125 moles of O₂

Oxygen is the limiting reactant, we need 3.125 moles but we only have 2.009 moles

Ratio is 5:3. 5 moles of O₂ produce 3 moles of CO₂

Therefore, 2.009 moles of O₂ must produce (2.009 .3) /5 = 1.21 moles of CO₂. Let's find out the volume, by Ideal Gases Law (STP are 1 atm and 273K, the standard conditions)

1 atm . V = 1.21 moles . 0.082 . 273K

V = (1.21 moles . 0.082 . 273K) / 1atm = 26.9 L

3 0
3 years ago
21 Given the following acid dissociation constants, which acid has the strongest conjugate base?
Makovka662 [10]
The correct answer is HCN.
7 0
3 years ago
What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10
vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

<h3>What are pH and pOH?</h3>

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, \rm pOH = 14 - pH

The pH of KOH can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the first case, the concentration of the KOH is 1. 87 \times  10^{-13}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times  10^{-13}\;\rm  M ]\\\\&= 12.73\end{aligned}

Hence, the pH of KOH is 12.73.

<u />

pOH of KOH can be calculated by the formula,

\rm pOH = \rm -log [OH^{-}]

The hydroxide concentration of the KOH solution is 5. 81 \times 10^{-3}\;\rm  M

Substituting value in the equation:

\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm  M ]\\\\&= 2.24 \end{aligned}

Hence, the pOH of KOH is 2.24

<u />

The pH of NaCl can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the third case, the concentration of the NaCl is 1. 00\times 10^{-7}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times  10^{-7}\;\rm  M ]\\\\&= 7 \end{aligned}

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

brainly.com/question/13885794

3 0
2 years ago
What is the temperature of liquid nitrogen?
motikmotik
Really darn cold lol
6 0
3 years ago
Help?
tino4ka555 [31]

Answer:

There is 52.33 grams of water produced.

Explanation:

Step 1: Data given

Mass of propane burned = 32.00 grams

Molar mass of propane = 44.1 g/mol

Oxygen is in excess

Molar mass of water = 18.02 g/mol

Step 2: The balanced equation

C3H8 + 5O2 → 4H2O + 3CO2

Step 3: Calculate moles of propane

Moles of propane = mass propane / molar mass of propane

Moles of propane = 32.00 grams / 44.1 g/mol

Moles of propane = 0.726 moles

Step 4: Calculate moles of H2O

Propane is the limiting reactant.

For 1 mol of propane consumed, we need 5 moles of O2 to produce 4 moles of H2O and 3 moles of CO2

For 0.726 moles of propane we'll have 4*0.726 = 2.904 moles of H2O

Step 5: Calculate mass of H2O

Mass of H2O = moles of H2O * molar mass of H2O

Mass of H2O = 2.904 moles * 18.02 g/mol

Mass of H2O = 52.33 grams

There is 52.33 grams of water produced.

3 0
3 years ago
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