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Aleks04 [339]
3 years ago
8

The density of mercury is 13.6 g/mL what is the density in lbs/L ( 1 lb hint =0.454 kg )

Chemistry
1 answer:
Vesna [10]3 years ago
6 0

Answer:

30.0\frac{lb}{L}

Explanation:

Hello,

In this case, since 454 g are equivalent to 1 pound and 1000 millilitres are equivalent to 1 liter, the required density is computed below by applying the corresponding conversion factor:

=13.6\frac{g}{mL} *\frac{1lb}{454g} *\frac{1000mL}{1L} \\\\=30.0\frac{lb}{L}

Regards.

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Explanation:

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3 years ago
An atom is the most __________ unit of living and nonliving things. (Help I will mark brainliest if ya help, and the first one t
ziro4ka [17]

The correct answer to your question is

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6 0
3 years ago
Read 2 more answers
2. if 0.20 m fe3 had been used instead of 0.020 m fe3 , how would the numerical value of the rate constant and the activation en
dezoksy [38]

the calculated value is Ea is 18.2 KJ and A is 12.27.

According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.

At 500K, K=0.02s−1

At 700K, k=0.07s −1

The Arrhenius equation can be used to calculate Ea and A.

RT=k=Ae Ea

lnk=lnA+(RT−Ea)

At 500 K,

ln0.02=lnA+500R−Ea

500R Ea (1) At 700K lnA=ln (0.02) + 500R

lnA = ln (0.07) + 700REa (2)

Adding (1) to (2)

700REa100R1[5Ea-7Ea] = 0.02) +500REa=0.07) +700REa.

=ln [0.02/0 .07]

Ea= 2/35×100×8.314×1.2528

Ea =18227.6J

Ea =18.2KJ

Changing the value of E an in (1),

lnA=0.02) + 500×8.314/18227.6

= (−3.9120) +4.3848

lnA=0.4728

logA=1.0889

A=antilog (1.0889)

A=12.27

Consequently, Ea is 18.2 KJ and A is 12.27.

Learn more about Arrhenius equation here-

brainly.com/question/12907018

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1 year ago
How does the density of air affect local weather patterns?
JulijaS [17]
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5 0
3 years ago
Convert 0.02 g/mL to the unit g/L.
Elenna [48]
I don't know but I think that 0.02 g/mL is 20 g/L because you multiply the 0.02 by a 100. That's how you get the Gram liter
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3 years ago
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