Answer:
Explanation:
Use the one-dimensional equation:
which says that the final velocity of a falling object is equal to its initial velocity times the acceleration of gravity times the time it takes to fall. We have the final velocity, -14.5 (negative because its direction is down and down is negative), initial velocity is 0 (because it was held still by someone before it was dropped), and acceleration is -9.8 (negative again, because direction is down while acceleration increases). Filling in:
-14.5 = 0 - 9.8t and
-14.5 = -9.8t so
t = 1.5 seconds
Answer:
1.7 g/cm³
Explanation:
Given that:
Density of substance = 3.4 g/cm³
Relative density to another substance = 2
Density of second substance=?
Let density of second substance = x
Relative density = density of substance / density of second substance
Relative density = density of substance / x
2.0 = 3.4g/cm³ / x
2 * x = 3.4 g /cm³
x = 3.4 g/cm³ ÷ 2
x = 1.7 g/cm³
Answer:
Acceleration=24.9ft^2/s^2
Angular acceleration=1.47rads/s
Explanation:
Note before the ladder is inclined at 30° to the horizontal with a length of 16ft
Hence angular velocity = 6/8=0.75rad/s
acceleration Ab=Aa +(Ab/a)+(Ab/a)t
4+0.75^2*16+a*16
0=0.75^2*16cos30°-a*16sin30°---1
Ab=0+0.75^2sin30°+a*16cos30°----2
Solving equation 1
(0.75^2*16cos30/16sin30)=angular acceleration=a=1.47rad/s
Also from equation 2
Ab=0.75^2*16sin30+1.47*16cos30=24.9ft^2/s^2
Answer:
Explanation:
GIVEN
Force (F) = 8 N
Distance (d) = 2.5 metres
Work done = ?
WE know we have the formula
work done = F * d
Work done = 8 * 2.5
= 20 Joule
Hope it helps :)