Answer:
-30 °C
Explanation:
First, we have to calculate the molality (m) of the solution. If the solution is 50% C₂H₆O₂ by mass. It means that in 100 g of solution, the are 50 g of solute (C₂H₆O₂) and 50 g of solvent (water).
The molar mass of C₂H₆O₂ is 62.07 g/mol. The moles of solute are:
50 g × (1 mol / 62.07 g) = 0.81 mol
The mass of the solvent is 50 g = 0.050 kg.
The molality is:
m = 0.81 mol / 0.050 kg = 16 m
The freezing-point depression (ΔT) can be calculated using the following expression.
ΔT = Kf × m = (1.86 °C/m) × 16 m = 30 °C
where,
Kf: freezing-point constant
The normal freezing point for water is 0°C. The freezing point of the radiator fluid is:
0°C - 30°C = -30 °C
 
        
             
        
        
        
To develop this problem we will apply the concepts related to angular kinematic movement, related to linear kinematic movement. Linear velocity can be described in terms of angular velocity as shown below,

Here,
v = Lineal velocity
= Angular velocity 
r = Radius
Our values are


Replacing to find the angular velocity we have,


Convert the units to RPM we have that


Therefore the angular speed of the wheels when the scooter is moving forward at 6.00 m/s is 955.41rpm
 
        
             
        
        
        
Answer:
Change in Velocity because 

Explanation:
Remeber area is length times Width. In this case, the area under a accleraton vs time graph is Accleration Times Time. Which is velocity
 
        
                    
             
        
        
        
Answer:
I think answer is zero
bcz momentum=mass×velocity 
body was initially at rest it means its velocity is zero
30×0=0