Question

Determine the change in internal energy of a monatomic ideal gas that expands from an initial volume of 1.53 m3 to a final volume of 2.87 m3. During this process the pressure of the gas remains at a constant value of 1.82 105 Pa.

Answer 1

Answer:

Internal energy will be $2.05\times 10^5Joule$

Explanation:

We have given that initial volume $v_1=1.53m^3$

And final volume $v_2=2.87m^3$

Pressure $p=1.02\times 10^5Pa$

Now change in volume $dv=2.87-1.53=1.34m^3$

We know that change in internal energy is given by

$\Delta U=\frac{3}{2}nR\Delta T$, here we know that

Work done $W=Pdv=nR\Delta T$

So $\Delta U=\frac{3}{2}PdV=\frac{3}{2}\times 1.02\times 10^5\times 1.34=2.05\times 10^5Joule$