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Airida [17]
3 years ago
7

Electrons have ---------------------- charge

Chemistry
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

.k;

Explanation:

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The diagram shows a lever. The mechanical advantage of the lever is (_____).
V125BC [204]

Answer:If the diagram shows 3 m and 6 m the answer would be 2.

Explanation:

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4 years ago
__Ba3N2 + __ H2O —-> __Ba(OH)2 + __ NH3
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is there a pic?

Explanation:

6 0
3 years ago
the reaction of 50 mL of gas with 50 mL of gas via the equation: Cl2(g) + C2H4(g) ➔ C2H4Cl2 (g) will produce a total of ________
spin [16.1K]

Explanation:

The given data is as follows.

      50 ml of Cl_{2},       50 ml of C_{2}H_{4}

And, it is known that at STP 1 mole of a gas occupies 22.4 L. Hence, moles present in 50 ml of gas are as follows.

          \frac{50}{22.4 \times 1000}      (As 1 L = 1000 ml)

          = 2.23 \times 10^{-3} moles

So, according to the given equation 2.23 \times 10^{-3} moles of Cl_{2} reacts with 2.23 \times 10^{-3} moles of C_{2}H_{4}.

Hence, moles of C_{2}H_{4}Cl_{2} is equal to the moles of C_{2}H_{4} and Cl_{2}.

Therefore, moles of C_{2}H_{4}Cl_{2} = 2.23 \times 10^{-3} moles

           1 mole of C_{2}H_{4}Cl_{2} = 22.4 L

   2.23 \times 10^{-3} moles = 22.4 \times 2.23 \times 10^{-3} moles        

                                = 50 ml of product

Thus, we can conclude that 50 ml of products if pressure and temperature are kept constant.

5 0
4 years ago
The length of a copper wire is 1.6 centimeters (cm). What is the length of this wire in meters (m)?
inna [77]
It is 0.016 in meters
3 0
3 years ago
If 16g of <img src="https://tex.z-dn.net/?f=CH_%7B4%7D" id="TexFormula1" title="CH_{4}" alt="CH_{4}" align="absmiddle" class="la
sammy [17]

43.56 grams of  are produced if 16g of  CH4 reacts with 64g of O2.

Explanation:

Balance equation for the reaction:

CH4 + 2O2⇒ CO2 +2H2O

Data given : mass of CH4 =16 grams  atomic mass = 16.04 grams/mole

                    mass of water 36 gram  atomic mass = 18 grams/moles

                   mass of CO2=?                atomic mass = 44.01 grams/mole

number of moles = \frac{mass}{atomic mass of one mole}    equation 1

number of moles in CH4

   n = \frac{16}{16.04}

       = 0.99 moles

Since combustion is done in presence of oxygen hence it is an excess reagent and methane is limiting reagent so production of CO2 depends on it.

From the equation

1 mole of CH4 gave 1 mole of CO2

O.99 moles of CH4 will give x moles of CO2

\frac{1}{1} = \frac{x}{0.99}

x = 0.99 moles of carbon dioxide

grams of CO2 = number of moles x atomic mass

                         = 0.99 x 44.01

                          = 43.56 grams of CO2 is produced.

4 0
3 years ago
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