The answer is B. Acid turns blue litmus paper to red
Answer:
To a certain extent absolutly. They can impact human health for the worse and more.
Answer:
yes it is true
Explanation:
evaporation occurs when burning liquid water changes into gas.
The 2.5 x 10²¹ molecules of CH₃OH have 0.00415 moles.
<h3>What is the mole concept?</h3>
- The Mole concept is used to express the amount of substance conveniently.
- A mole is defined as the amount of substance that contains exactly 6.022 x 10²³ elementary particles of the given substance. Here, elementary particles refer to atoms, molecules, or ions.
- This fixed number 6.022 x 10²³ is known as Avogadro Number and is denoted by

<h3>How to calculate the number of moles?</h3>
The number of moles is given by

When given mass = molar mass of a substance, then no of moles is equal to 1 which is equivalent to 6.022 x 10²³.
We also know,
1 mole has 6.022 x 10²³ molecules of CH₃OH
According to the mole concept,
6.022 x 10²³ molecules of CH₃OH is equal to 1 mole
2.5 x 10²¹molecules of CH₃OH is equal to
moles
Thus, 2.5 x 10²¹molecules of CH₃OH are equal to 4.15 x 10⁻³ moles or 0.00415 moles
Learn more about the mole concept:
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Those Hydrogen atoms which are present at alpha position to carbonyl group are mildly acidic in nature. When such acidic proton containing carbonyl compounds are treated with strong base, they yield enolates. The negative charge created on alpha carbon resonates and shifts to carbonyl oxygen resulting in formation of carbon double bond carbon.
In <span>tert−butyl methyl ketone there are two carbons at each alpha position. Among these two carbons only methyl carbon contains hydrogen atoms while the second one is bonded to further three carbons making it Quaternary carbon. The base abstracts proton from methyl group and enolate is formed.
</span>tert−butyl methyl ketone in this case acts as acid, Hydroxyl ion acts as base, while the enolate generated is the conjugate base of <span>tert−butyl methyl ketone and Water produced is the conjugate acid of hydroxide ion.</span>