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Airida [17]
3 years ago
7

Electrons have ---------------------- charge

Chemistry
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

.k;

Explanation:

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¡que es el vitalismo ?
Brrunno [24]
<h2>Answer:</h2><h3>Vitalism-</h3>
  • A theory that an organic molecule cannot be produced from inorganic molecules, but instead can only be produced from a living organism or some part of a living organism. The theory was disproved in the early part of the 19th century<em>.</em>

<em>Translated</em><em>~</em>

  • Teoría de que una molécula orgánica no se puede producir a partir de moléculas inorgánicas, sino que solo se puede producir a partir de un organismo vivo o de alguna parte de un organismo vivo. La teoría fue refutada a principios del siglo XIX.
3 0
3 years ago
What fraction of a Sr-90 sample remains unchanged after 87.3 years
jolli1 [7]
The answer is 1/8.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
<span>t_{1/2} = 28.8 years

We need:
n = ?
x = ?
</span>
We could first use the second equation, to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{87.3 years}{28.8 years}
⇒ n=3.03
<span>⇒ n ≈ 3
</span>
Now we can use the first equation to calculate the remained amount of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^3
⇒x= \frac{1}{8}<span>
</span>
8 0
4 years ago
URGENT!! This is timed, PLEASE HELP!
Andrews [41]

Answer:

99.24 gm of nitrogen .

Explanation:

molecular weight of ammonia = 17 , molecular weight of nitrogen = 28.

2 NH₃(g) + 3 CuO(s) → 1N₂(g) + 3 Cu(s) + 3 H₂O(g)

2 x 17 gm                      28 gm

( 34 gm )

34 gm of ammonia forms 28 gms of nitrogen

1 gm of ammonia   forms 28 / 34 gms of nitrogen

120.51 gn of ammonia forms 28 x 120.51 / 34 gms of nitrogen

28 x 120.51 / 34 gms

= 99.24 gms of nitrogen will be formed .

8 0
4 years ago
Balancing
Kruka [31]
2 in front of H2. Technically nothing in front of O2 otherwise put a 1 then a 2 in front of H2O

2H20 + 1O2 —— > 2H2O
5 0
3 years ago
What is the limiting reactant when 19.9 g CuO react with 2.02 g H2?
Harlamova29_29 [7]

Answer:

Explanation:

use the equation

moles = mass/mr

=19.9/79.5

=0.250moles of CuO

then do the same for

H = 2.02/1

=2.02

so CuO is the limiting reagent because there is less amount of it.

Hope this helps  :)

4 0
3 years ago
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