True, also fizzing and heat being released
Answer:
The image is formed by a convex lens with the object at 2F.
- Image will be of same size as the object
- Image will be real and upside down.
You've listed a lot of data here, in both metric and customary units,
and I'm not even sure it's all needed. Let me try and boil it down:
Pressure on a surface =
(total force on a surface) divided by (area of the surface).
The answer to the question is the pressure expressed in pascals.
There's actually enough information here to answer the question
in 2 different ways. We could ...
-- simply convert (0.03 pound per inch²) to pascals, or
-- go through the whole calculation of force, area, and then their quotient.
To me, converting 0.03 psi to Pa looks easier.
-- 1 pascal = 1 newton / 1 meter²
-- On Earth, 1 kilogram of mass weighs 9.8 Newtons and 2.2 pounds.
From this, we can calculate that
2.2 pounds of force = 9.8 newtons of force.
1 pound = 4.45 newtons
(0.03 pound/inch²) x (4.45 newton/pound) x (1inch/2.54cm)² x (100cm/1m)² =
(0.03 x 4.45 x 1² x 100²) / (2.54² x 1²) newton/meter² = 206.9 Pa .
Answer:
Explanation:
Given
Electric Field 
velocity 
mass of electron 
Force on a charge Particle moving in Magnetic Field
![F=e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]](https://tex.z-dn.net/?f=F%3De%5Cleft%20%5B%20%5Cvec%7BE%7D%2B%5Cleft%20%28%20%5Cvec%7Bv%7D%5Ctimes%20%5Cvec%7BB%7D%5Cright%20%29%5Cright%20%5D)
![a=\frac{e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]}{m}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Be%5Cleft%20%5B%20%5Cvec%7BE%7D%2B%5Cleft%20%28%20%5Cvec%7Bv%7D%5Ctimes%20%5Cvec%7BB%7D%5Cright%20%29%5Cright%20%5D%7D%7Bm%7D)
![a=\frac{1.6\times 10^{-19}\left [ 2\hat{i}+5.4\hat{j}+\left ( 8\hat{i}\times 0.4\hat{k}\right )\right ]}{9.1\times 10^{-31}}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B1.6%5Ctimes%2010%5E%7B-19%7D%5Cleft%20%5B%202%5Chat%7Bi%7D%2B5.4%5Chat%7Bj%7D%2B%5Cleft%20%28%208%5Chat%7Bi%7D%5Ctimes%200.4%5Chat%7Bk%7D%5Cright%20%29%5Cright%20%5D%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%7D)
Yea I would love to help u
