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ozzi
3 years ago
14

Wood is burned to heat a house. this is a example of the conversion of

Physics
2 answers:
Sergio039 [100]3 years ago
8 0

Answer: heat energy to chemical energy

Explanation: not sure but hope this helps :)

LenaWriter [7]3 years ago
7 0

Answer:Combustion

Explanation:The chemical reaction is called combustion and requires oxygen. Combustion changes the potential chemical energy into kinetic energy in form of heat.

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Fill in the blanks to complete each statement about the heating of Earth's surface.
cricket20 [7]

Answer:

absorption and insolation.

Explanation:

6 0
4 years ago
Why are the alkali metals likely to react with group 17 elements?
Rudiy27

Answer:

Because alkali metals are so reactive, they are found in nature only in combination with other elements. They often combine with group 17 elements, which are very “eager” to gain an electron.

Explanation:

hope this helps you if it does please mark brainliest

7 0
3 years ago
Suppose the sphere is electrically neutral. Is it attracted to
Elden [556K]

Answer:

No, it is not attracted.

Explanation:

If any sphere is electrically neutral it is not attracted. The materials which are attracted by magnet are called magnetic material whereas which are not attracted are called non magnetic material. Sphere made up of non magnetic materials such as glass, wood, paper will not attracted weather is kept near north pole or near south pole.

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3 years ago
Suppose a nonconducting sphere, radius r2, has a spherical cavity of radius r1 centered at the sphere's center. Assuming the cha
leva [86]

Answer:

Explanation:

a ) Between r = 0 and r = r₁

Electric field will be zero . It is so because no charge lies in between r = 0 and r = r₁ .

b ) From r = r₁ to r = r₂

At distance r , charge contained in the sphere of radius r

volume charge density x 4/3 π r³

q = Q x r³ / R³

Applying Gauss's law

4πr² E = q / ε₀

4πr² E = Q x r³ / ε₀R³

E= Q x r / (4πε₀R³)

E ∝ r .

c )

Outside of r = r₂

charge contained in the sphere of radius r = Q

Applying Gauss's law

4πr² E = q / ε₀

4πr² E = Q  / ε₀

E = Q  / 4πε₀r²

E ∝ 1 / r² .

6 0
3 years ago
How does the law of conservation of energy apply to a light bulb? the electrical energy put into the light bulb equals the light
andrew-mc [135]
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7 0
3 years ago
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