We will apply the equation:2as = v² - u²v = √(2as + u²)v = √(2 x 4 x 400 + 13²)v = 58 m/s
Answer:
The answer for a classical particle is 0.00595
Explanation:
The equation of the wave function of a particle in a box in the second excited state equals:
ψ(x) = ((2/L)^1/2) * sin((3*pi*x)/L)
The probability is equal to:
P(x)dx = (|ψ(x)|^2)dx = ((2/L)^1/2) * sin((3*pi*x)/L) = (2/L) * sin^2((3*pi*x)/L) dx
for x = 0.166 nm
P(x)dx = (2/0.167) * sin^2((3*pi*0.166)/0.167) * 100 pm = 0.037x10^-3
for x = 0.028 nm
P(x)dx = (2/0.167) * sin^2((3*pi*0.028)/0.167) * 100 pm = 11x10^-3
for x = 0.067 nm
P(x)dx = (2/0.167) * sin^2((3*pi*0.067)/0.167) * 100 pm = 3.99x10^-3
therefore, the classical probability is equal to:
(1/L)dx = (1/0.167)*100 pm = 0.00595
The shortest frequency is present in the wave with the highest energy.
Therefore, the answer is X-Rays.
Answer: 3 seconds
Explanation:
Initial velocity(u) of projectile A in vertical direction = 0m/s
acceleration due to gravity a=g=9.81m/s^2
Time taken(t) of projectile A = 3s
Initial velocity of projectile B = 0m/s(vertical direction)
We can get height of cliff using parameters of projectile A since it's the same location.
Height(S) = u×t + 0.5×a×t^2
u =0
S= 0.5×9.81×3^2 = 44.145m
Time taken for projectile B to reach the ground:
S = u×t + 0.5×a×t^2
u =0, S=44.145m, a=9.81m/s^2
44.145 = 0.5×9.81×t^2
44.145 = 4.905×t^2
44.145 ÷ 4.905 = t^2
9 = t^2
t = sqrt(9)
t = 3seconds
A.) restriction because your can’t get to your place!
