Answer:
i can help you but go to the school Grade 4 like my pro
Explanation:
Answer:
Hey
Your answer would be
The moon is not visible
due to Earth's shadow=lunar eclipse
The sun is not visible due
to the moon=solar eclipse
The moon is on the side of
Earth opposite the sun=new moon
The moon and sun are on
the same side of Earth=full mon
Answer:
Final distance from the origin: 10.82 km. the vector points as shown in the attached image.
Angle with respect to the east: 
Explanation:
Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.
So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.
We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:
Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.
Now, to find the value of the angle 
, we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:
Now we can find the value of the angle by using the arctan function:
Answer:d
Explanation:
From Gauss law Electric field inside a surface is directly proportional to the charge enclosed in it.
Electric field inside a spherical shell is zero and hence there is no charge inside the spherical shell because q charge induces a -q charge on inside surface of spherical shell.
and to counter it there is q charge on the surface. So total charge outside the surface is Q+q
Answer :
<em>(b) 4d orbitals would be larger in size than 3d orbitals</em>
<em>(e) 4d orbitals would have more nodes than 3d orbitals</em>
Explanation :
As we move away from one orbital to another, the distance between nucleus and orbital increases. So, 4d orbitals would be far to the nucleus than 3d orbitals.
Hence, 4d orbitals would be larger in size than 3d orbitals.
Number of nodes is any orbital is n - 1 where, n is principal quantum number.
So, number of orbital in 4d is 3.
And number of orbital in 3d is 2.
So, options (b) and (e) are correct.
