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Vesna [10]
3 years ago
9

In acceleration time graph curve upward shows _______ acceleration

Physics
2 answers:
olganol [36]3 years ago
7 0

Answer: increase

Explanation:

kondor19780726 [428]3 years ago
4 0

Answer:

                          rapid

Explanation:

it seems like it.

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Which statements are true about the speed of a wave?
Pie
I guess b tell me if I’m wrong
4 0
3 years ago
Read 2 more answers
A water wave traves with a length of 10 meters and a frequency of 30 hertz, what is the velocity of the wave?
UNO [17]

Answer: 300 m/s

Explanation:

Given that:

length of water wave (λ) = 10 metres

Frequency of water wave (F) = 30 Hertz

Velocity of water wave (V) = ?

The velocity of a wave is the distance covered by the wave in one second. It is measured in metre per second, and represented by the symbol V. It is related to frequency and wave length by the formula: V = F λ

V = 30 Hertz x 10 metres

V = 300 m/s

Thus, the velocity of the water wave is 300 m/s

4 0
3 years ago
Now assume that the frictional force f is not at its maximum value. What is the relation between the torque Ï„ applied to each w
leva [86]

Answer:

a)The direction the frictional force will acts is in the positive x direction.

Explanation:

a)The direction the frictional force will acts is in the positive x direction

b)in the horizontal direction, the total force F(total) is equal to 4times the frictional force in the wheel.

F(total)=4f

''f'' is taken as the frictional force.

c)4times the normal force on each wheel minus the acceleration equals zero i.e 4N(wheel)-a=0

=4N(wheel)-mg=0

d) torque is the force that tends to bend rotation

ζ=rf

but acceleration=4×frictional force

cross multiply

f=ζ/r

f=ma/4

ma/4=ζ/r

a=4ζ/r

5 0
3 years ago
Read 2 more answers
16.
Sholpan [36]

Answer:

doing her homework/finding time to do important things

4 0
3 years ago
A 2100 kg car starts from rest and accelerates at a rate of 2.6 m/s2 for 4.0 s. Assume that the force acting to accelerate the c
Reika [66]
When the system is experiencing a uniformly accelerated motion, there are a set of equations to work from. In this case, work is energy which consist solely of kinetic energy. That is, 1/2*m*v2. First, let's find the final velocity.

a = (vf - v0)/t
2.6 = (vf - 0)/4
vf = 10.4 m/s

Then W = 1/2*(2100 kg)*(10.4 m/s)2
W = 113568 J = 113.57 kJ
8 0
3 years ago
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