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Natasha_Volkova [10]
3 years ago
14

Xg of U and 3.795 g of O combine to form 20.00 g of

Chemistry
1 answer:
Deffense [45]3 years ago
8 0

The percent composition of Uranium in U308 = C. 81.03%

<h3>Further explanation</h3>

Given

X g of U

3.795 g of O

20.00 g of  U308

Required

The percent composition of Uranium

Solution

mass of Uranium in U308 :

= mass of U308 - mass of O

= 20 g - 3.795 g

= 16.205 g

The percent composition :

\tt \%U=\dfrac{mass~U}{mass~U308}\times 100\%

%U = (mass U/mass U308) x 100%

%U= (16.205/20) x 100%

%U = 81.025≈81.03

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Answer:

V₂ =31.8 mL

Explanation:

Given data:

Initial  volume of gas = 45 mL

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Solution:

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According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

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8 0
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<em></em>

I hope it helps!

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