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mezya [45]
3 years ago
12

A student has a rectangular block. It is 3.00 cm wide, 400.0 mm tall, and 0.25 m long. It has a mass of 600.0 g. What is the den

sity (g/mL) of the rectangular block? (1cm^3 = 1 mL) ​
Chemistry
1 answer:
Aneli [31]3 years ago
4 0

Explanation:

deg dragster Zbigniew

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What is the difference between pure and applied chemistry?
bekas [8.4K]

Answer:

Explanation:

The major difference between pure and applied chemistry is the purpose and intent of the study.

Pure chemistry deals with the study of matter, matter transformations, and interactions between the different materials of the world, for only the sake of gaining empirical knowledge about the various substances that exist in the world. It does not really seek to apply this knowledge to do anything industrial.

Applied chemistry is the study of chemistry with the aim of utilizing this knowledge to solve the various problems that man faces. This approach of study is not for knowledge sake alone, rather it is for industrial application

3 0
3 years ago
Determine what forces are present in this situation : an elevator is rising at a constant speed; the elevator is the object in t
alexandr1967 [171]
The correct answer for the given question would be option A. The forces that are present in the given situation above which is an elevator rising at a constant speed, are gravity and tension. Gravity is the force that pulls all matter together. Tension is the <span>pulling force transmitted axially. Hope this is the answer that you are looking for.</span>
7 0
3 years ago
Read 2 more answers
A 98.0°C piece of cadmium (c=.850J/g°C) is placed in 150.0g of 37.0°C water. After sitting for a few minutes, both have a temper
Eduardwww [97]
The answer is 19.9 grams cadmium. 
Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:
     heat lost by cadmium = heat gained by the water
     -qcadmium = qwater
Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:
     -qcadmium = qwater
     -(mcadmium)(0.850J/g°C)(38.6°C-98.0°C)) = 150.0g(4.18J/g°C)(38.6°C-37.0°C)
     mcadmium = 19.9 grams
3 0
3 years ago
The data in the table are the result of a paramecium being placed in a hypertonic salt solution.
kolezko [41]
<span>the answer is
C. The bar for very low concentration is twice the height of the bar for medium concentration.

proof
</span>
<span>
</span>
<span>Medium--------------------15

</span>Very Low-------------------30 = 2<span /> x 15 (<span>Medium)
</span>



3 0
3 years ago
Read 2 more answers
Free radical mono-halogenation of an alkane is typically conducted using bromine versus chlorine because A.the bromine radical i
Nimfa-mama [501]

Answer:Free radical mono-halogenation of an alkane is typically conducted using bromine versus chlorine because the bromine radical is less reactive and therefore more selective.

Explanation: Halogenation occurs when a halogen replaces  one or more hydrogen atoms in an organic compound ie  chlorine or  bromine with the reactivity of the halogens decreasing  in the order of  F2 > Cl2 > Br2 > I2

Since fluorine reacts  explosively making it is difficult to control, and iodine is unreactive. Free radical mono-halogenation of an alkane is typically conducted using bromine versus chlorine  with Chlorination  ie chlorine radical being more reactive and not selective and the Bromination of alkanes ie bromine radical  occurring similarly but slower and less reactive but  more selective which is due to the fact that a bromine atom is less reactive in  the hydrogen abstraction  than a chlorine atom evidence in the  higher bond energy of H-Cl than H-Br.

5 0
3 years ago
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