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Kryger [21]
1 year ago
15

What is the resistance of a carbon rod at 25.8 ∘C if its resistance is 0.0200 Ω at 0.0 ∘C ?

Physics
1 answer:
torisob [31]1 year ago
4 0

0.02020 ohm is the resistance of a carbon rod at 25.8 ∘C if its resistance is 0.0200 Ω at 0.0 ∘C.

<h3 /><h3>What is a resistor?</h3>

A resistor is an electrical component that controls or restricts how much electrical current can pass across a circuit in an electronic device. A specified voltage can be supplied via resistors to an active device like a transistor.

The temperature of the resistor varies based on the variation in the temperature. The equation that describes the relationship between the two of them is:

R = R0[1+ alpha(T-T0)]  where:

R is the new resistance we are looking for

alpha is the temperature coefficient of resistance. For carbon rod, alpha = ₋ 4.8 x 10^{-4}(1/°c)

T0 is the standard temperature =25.8°C

R0 is the resistance at T0 = 0.0200 ohms

T is the temperature at which we want to get R = 0

Substitute in the equation to get R as follows:

R = 0.0200 [1+( ₋ 4.8 x 10^{-4}) (0-25.8)] = 0.02020 ohm

To know more about resistance refer to: brainly.com/question/11431009

#SPJ1

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Answer:

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Explanation:

1.) Given that the

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Stopping distance = 1 + 3 = 4m

2.) Given that the

Stopping distance = 52 m

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Breaking distance = 76 - 14 = 62m

It take the brakes 62m to slow the car down to a stop.

4.) Given that a lorry travels 28m when stopping from a speed of 4m/s. If its braking distance was 18m, what was the driver’s reaction time?

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Reaction time = 10/4

Reaction time = 2.5 s

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5 0
3 years ago
A Brayton cycle has air into the compressor at 95 kPa, 290 K, and has an efficiency of 50%. The exhaust temperature is 675 K. Fi
motikmotik

Answer:

The specific heat addition is 773.1 kJ/kg

Explanation:

from table A.5 we get the properties of air:

k=specific heat ratio=1.4

cp=specific heat at constant pressure=1.004 kJ/kg*K

We calculate the pressure range of the Brayton cycle, as follows

n=1-(1/(P2/P1)^(k-1)/k))

where n=thermal efficiency=0.5. Clearing P2/P1 and replacing values:

P2/P1=(1/0.5)^(1.4/0.4)=11.31

the temperature of the air at state 2 is equal to:

P2/P1=(T2/T1)^(k/k-1)

where T1 is the temperature of the air enters the compressor. Clearing T2

11.31=(T2/290)^(1.4/(1.4-1))

T2=580K

The temperature of the air at state 3 is equal to:

P2/P1=(T3/T4)^(k/(k-1))

11.31=(T3/675)^(1.4/(1.4-1))

T3=1350K

The specific heat addition is equal to:

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3 years ago
Which of the following correctly compares the uses of bar graphs versus pie charts?
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2 years ago
A tennis ball bounces on the floor three times. If each time it loses 22.0% of its energy due to heating, how high does it rise
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Answer:

H = 109.14 cm

Explanation:

given,                                                            

Assume ,                                                            

Total energy be equal to 1 unit                                

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Balance after third collision = 0.78 ^3 unit

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H be the height achieved after 3 collision

0.475 ( m g h) = m g H                  

H = 0.475 x h                                    

H = 0.475 x 2.3 m                          

H = 1.0914 m                      

H = 109.14 cm                      

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