Answer:
A) 
= 77.6 ⁰C
, B) = 341.6 C
Explanation:
The thermal expansion is given by
ΔL = α L₀ ΔT
The thermal expansion coefficient for polycarbonate varies between 65 and 70 10⁻⁶ ⁰C⁻¹ and for cast iron 12 10⁻⁶ C⁻¹
Let's look for the final temperature that says same shift change
ΔT = ΔL / α L₀
- T₀ = ΔL /α L₀
= T₀ + ΔL / α L₀
Let's calculate for each material
A) Polycarbonate use as thermal expansion coefficient 70 10⁻⁶ C⁻¹
= 23.0 + 0.0268 / (70 10⁻⁶ 7.01)
= 23.0 + 54.6
= 77.6 ⁰C
B) cast iron with thermal expansion coefficient 12 10⁻⁶ C⁻¹
= 23.0 + 0.0268 / (12 10⁻⁶ 7.01)
= 23.0 + 3.1859 10²
= 341.6 C
Answer:
2.5 cm
40 D
Explanation:
When the radius of curvature of a lens is divided by 2 we get the focal length of the lens.
Focal length is given by
The focal length of the lens is 2.5 cm
When we divide 1 by the focal length in the unit of meters we get the power of a lens
Power of a lens is given by
The power of the lens is 40 D
The final velocity is +15.0 m/s
Explanation:
The motion of the cart is a uniformly accelerated motion (=at constant acceleration), therefore we can use the following suvat equation:
where
v is the velocity at time t
u is the initial velocity
a is the acceleration
t is the time
For the cart in this problem, we have:
u = +3.0 m/s (initial velocity)
(acceleration)
t = 8.0 s (time)
Substituting, we find the final velocity:
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Correct answer is A.
In a parallel circuit, the voltage is same across all the branches however the current in each branch is different and depends on the resistance of that branch. The higher the resistance, the lower the current.
In a series circuit, the voltage across each resistive element is different and depends on the resistance of that element. Higher the resistance, larger will be the voltage drop. However, the current throughout the series circuit is the same as there is only path in a series circuit.
Points to Remember:
1) In series circuit current remains the same and voltage varies
2) In parallel circuit voltage remains the same and current varies
We have that for the Question "A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that the minimum force that must be applied on the <em>book is</em>
From the question we are told
A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal
Generally the equation for the Force is mathematically given as
F=44N
Therefore
the minimum force that must be applied on the <em>book is</em>
F=44N
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