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3 years ago

How can water be used for energy???

Physics

2 answers:

Alla [95]3 years ago

4 0

Answer:

Water can be used for energy by placing dams in tidal areas.

Explanation:

Hydraulic energy is the energy supplied by the movement of water, in all its forms: waterfalls, rivers, sea currents, tides, waves, etc. This movement can be used directly, for example with a water mill, or more commonly be converted, for example into electrical energy in a hydroelectric plant.

Hydraulic energy is in fact a kinetic energy linked to the movement of water as in ocean currents, rivers, tides, waves or the use of potential energy as in the case of waterfalls and dams.

stellarik [79]3 years ago

3 0

<span>by placing dams in tidal areas. ITS the only one that has anything to do with water</span>

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What is a core sample ????

kap26 [50]

Answer:

Core samples are small portions of a formation taken from an existing well and used for geologic analysis. The sample is analyzed to determine porosity, permeability, fluid content, geologic age, and probable productivity of oil from the site. ... Core samples reveal the physical and chemical nature of the rock.

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3 years ago

calculate the pressure exerted on the floor when a elephant who weighs 6000N stands on 1 foot which has a area of 20m

Roman55 [17]

Answer:

1500n

Explanation:

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2 years ago

[1] The assembly starts from rest and reaches an angular speed of 150 rev/min under the action of a 20-N force T applied to the

ExtremeBDS [4]

Answer:

t = 5.89 s

Explanation:

To calculate the time, we need the radius of the pulley and the radius of the sphere which was not given in the question.

Let us assume that the radius of the pulley ( $r_p$ ) = 0.4 m

Let the radius of the sphere (r) = 0.5 m

w = angular speed = 150 rev/min = (150 × 2π / 60) rad/s = 15.708 rad/s

Tension (T) = 20 N

mass (m) = 3 kg each

$\int\limits^0_t {Tr_p} \, dt=H_2-H_1\\( Tr_p)t=4rm(rw)\\( Tr_p)t=4r^2mw$

$t = \frac{4r^2mw}{Tr_P}$

Substituting values:

$t = \frac{4r^2mw}{Tr_P}= \frac{4*(0.5)^2*3*15.708}{20*0.4}=5.89s$

7 0

3 years ago

Read 2 more answers

Consider this situation: Four ropes, each attached to the end

faust18 [17]

The forces acting on the elevator are:

Gravity force

Tension force

Air resistance

Explanation:

Let's go through each of the forces listed and see which ones are acting on the elevator.

Normal force: NO. The normal force is a force exerted by a surface whenever there is another object "pushing" on it. For instance, when a box is at rest on a table, the box is "pushing" on the table (due to its weight), and the table "pushes back" on the box, upward, in order to balance its weight: this is the normal force. In this case, the elevator is lifted, so it is not pushing on anything, therefore there is no normal force.
Gravity force: YES. The force of gravity acts on every object located in the gravitational field of the Earth; it pulls downward, and its magnitude is $mg$ , where m is the mass of the object and g is the acceleration of gravity.
Applied force: NO. Here there is no applied force, since there is nobody "pushing" or "pulling" the elevator.
Friction force: NO. As we are considering the forces on the elevator, and the elevator is not sliding against any surfaces, there is no force of friction. (The force of friction acts whenever there are two surfaces sliding against each other, which is not the case here)
Tension force: YES. The tension force is the force exerted by a rope or a string when pulling an object. In this case, there are four ropes pulling the elevator, therefore there are 4 forces of tension acting on the elevator, upward.
Air resistance: YES. As the elevator is moving through the air, the interaction between the molecules of air with the surface of the elevator produces a force (called air resistance) that "resists" the motion of the elevator, therefore pushing downward. However, the magnitude of this force is negligible in this case.