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3 years ago

How can water be used for energy???

Physics

2 answers:

Alla [95]3 years ago

4 0

Answer:

Water can be used for energy by placing dams in tidal areas.

Explanation:

Hydraulic energy is the energy supplied by the movement of water, in all its forms: waterfalls, rivers, sea currents, tides, waves, etc. This movement can be used directly, for example with a water mill, or more commonly be converted, for example into electrical energy in a hydroelectric plant.

Hydraulic energy is in fact a kinetic energy linked to the movement of water as in ocean currents, rivers, tides, waves or the use of potential energy as in the case of waterfalls and dams.

stellarik [79]3 years ago

3 0

<span>by placing dams in tidal areas. ITS the only one that has anything to do with water</span>

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Jobisdone [24]

Answer:

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Explanation:

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3 years ago

Pls help answer embed <br>

Savatey [412]

Answer:

C = 1.01

Explanation:

Given that,

Mass, m = 75 kg

The terminal velocity of the mass, $v_t=60\ m/s$

Area of cross section, $A=0.33\ m^2$

We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,

Weight of the object = drag force

R = W

$\dfrac{1}{2}\rho CAv_t^2=mg$

Where

$\rho$ is the density of air = 1.225 kg/m³

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So,

$C=\dfrac{2mg}{\rho Av_t^2}\\\\C=\dfrac{2\times 75\times 9.8}{1.225\times 0.33\times (60)^2}\\\\C=1.01$

So, the drag coefficient is 1.01.

5 0

3 years ago

What is the relationship among

lawyer [7]

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3 years ago

The kicker now kicks the ball with the same speed as in the number of 4,but at 60.0°from the horizontal or 30.0° from the vertic

stealth61 [152]

Answer:

Explanation:

1) The time of flight equation for projectile motion can be used here to find total time in air.

t = 2vsin∅ / g

where v is speed, Ф is launch angle

t = 2×4×sin 60 / 9.8

t = 0.71 seconds

2) Distance where it hit the ground is called as range and has the following standard equation

D = v² sin2Ф/g

D = 4²sin 2×60 / 9.8

D = 1.41m

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3 years ago

A phone cord is 4.89 m long. The cord has a mass of 0.212 kg. A transverse wave pulse is produced by plucking one end of the tau

slega [8]

Answer:

Tension in Cord=174 N

Explanation:

Given Data

L (Phone Cord Length)=4.89 m

m (Cord Mass)=0.212 Kg

T (Time for four trips)=0.617 s

Tension=?

Solution

V=λ×f

$V=\frac{8*4.89}{0.617}\\ V=63.4m/s$

$Sigma=\frac{mass}{length}\\ Sigma=\frac{0.212}{4.89}\\ Sigma=0.0433 \frac{kg}{m}$

$Wave Speed=\sqrt{\frac{Tension}{Sigma} }\\ \\V=\sqrt{\frac{T}{Sigma} }\\ V^{2}=\frac{T}{Sigma}\\ T=V^{2}*Sigma\\ T=(63.4)^{2}*(0.0433)\\ T=174 N$

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3 years ago