Answer:
Explanation:
According to the question
net force F = 2.20×10^6 N
displacement 
from figure , the horizontal forces are same in magnitude and opposite direction.
so , neglect these two forces.
we can take only vertical components of the force.
total force F' = F cos 19° + F cos 19°
= 2×F×cos 19° ................. (1
therefore , total work is
W = F'S
= (2F cos19)×S
I think they can use more durable materials.
Answer:The speed if hailstone dependly largely on its size. A hailstone with a diameter of 0.39 inches,falls wit a speed of 20mph while a hailstone with 3.1 inches in diameter falls at a speed of 110mph.
No speed does not depend on the distance that the hailstone falls.
Explanation: There are other factors that affect the speed of the falling hailstone apart from its size.They are:
1. Friction between the air and the hailstone
2. Wind condition( windy or moist air)
3. The rate at which it melts falling.
(30, 5)
(10, 1)
change of y / change of x
= (30 - 10) / (5 - 1)
= 20 /4
= 5
