All categories

3 years ago

What is equivalent to 21/12

Physics

2 answers:

Harrizon [31]3 years ago

7 0

21/12 is equal to 1 3/4 hope this helps!

Allushta [10]3 years ago

7 0

I'm not sure if you have specific options, but you can multiply or divide the top and bottom by the same number to get equivalent fractions.

EG: Multiply both by 2 and you get 42/24 which is equivalent to 21/12.

You might be interested in

What is the sum of all forces acting on an object and direction

babunello [35]

The sum of all forces on an object is the net force or resultant force. If all the forces cancel out , resultant force is zero , otherwise unbalanced force will cause acceleration of object .

Force is the vector, has both direction and magnitude.

3 0

3 years ago

A particle with charge q = +5e and mass m = 8.2×10-26 kg is injected horizontally with speed 1.1×106 m/s into the region between

loris [4]

Answer:

d = 1.27m

Explanation:

Given m = 8.2×10-26kg, v = 1.1×10⁶m/s, q = +5e = 5×1.6×10‐¹⁹ C.

E = 49kN/C = 49000N/C

The displacement is given by

d = 1/2× mv²/qE = 1/2 × 8.2×10-²⁶ × (1.1×10⁶)²/(5×1.6×10-¹⁹ ×49000) = 1.27m

3 0

3 years ago

Read 2 more answers

A light-rail commuter train accelerates at a rate of 1.35 m/s2. How long does it take to reach its top speed of 80.0 km/h, start

Alona [7]

Answer:

16.46 seconds.

13.46 seconds

2.67 m/s²

Explanation:

Acceleration = a = 1.35 m/s²

Final velocity = v = 80 km/h = $80\frac{1000}{3600}=\frac{200}{9}\ m/s$

Initial velocity = u = 0

Equation of motion

$v=u+at\\\Rightarrow \frac{200}{9}=0+1.35t\\\Rightarrow t=\frac{\frac{200}{9}}{1.35}=16.46\ s$

Time taken to accelerate to top speed is 16.46 seconds.

Acceleration = a = -1.65 m/s²

Initial velocity = u = 80 km/h= $80\frac{1000}{3600}=\frac{200}{9}\ m/s$

Final velocity = v = 0

$v=u+at\\\Rightarrow 0=\frac{200}{9}-1.65t\\\Rightarrow t=\frac{\frac{200}{9}}{1.65}=13.46\ s$

Time taken to stop the train from top speed is 13.46 seconds

Initial velocity = u = 80 km/h= $80\frac{1000}{3600}=\frac{200}{9}\ m/s$

Time taken = t = 8.3 s

Final velocity = v = 0

$v=u+at\\\Rightarrow 0=\frac{200}{9}+a8.3\\\Rightarrow a=\frac{-\frac{200}{9}}{8.3}=-2.67\ m/s^2$

Emergency deceleration is 2.67 m/s²

3 0

3 years ago

Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station 780 m diameter rotatin

ser-zykov [4K]

Answer:1.513 rps

Explanation:

Given

Diameter of cylindrical space $d=780\ m$

When the station rotates it creates centripetal acceleration which is given by

$a_c=\omega ^2r$

Now it must create the effect of gravity so

$g=\omega ^2r$

$\omega =\sqrt{\frac{g}{r}}$

$\omega =0.158\ rad/s$

and $\omega =\frac{2\pi N}{60}$

Thus $N=\frac{4.755}{3.142}$

$N=1.513\ rps$

5 0

3 years ago

If the length of a ramp is increased, what will happen to the input force?

Art [367]

The input force will increase too because the more the ramp is increasing the more force is being put on the object going down the ramp... hope this helps ^-^

3 0

3 years ago