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GREYUIT [131]
3 years ago
13

Why are the elements 57 through 71 and 89 through 102, found separately at the bottom of the table?

Chemistry
1 answer:
Dovator [93]3 years ago
8 0
Elements from 57 to 71 are Lanthanoids and from 89 to 103 are Actinoids. Simply I would say Actinoids have less similarity in chemical properties than Lanthanoids. On the other hands, Actinoids have randomized chemical strutural bonds.
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What is denser kerosene, fuel oil, or butane
frez [133]
I'm not sure what type of fuel you're talking about. If you mean fossil fuel then kerosene has the highest density of all of the things you listed.
3 0
3 years ago
Read 2 more answers
When electrons are lost, a____ion is formed.
kati45 [8]

Answer:

Positive; negative

Explanation:

When electrons are lost, a positive ion is formed. A positive ion is called a cation.

When electrons are gained, a negative ion is formed. A negative ion is called an anion.

3 0
3 years ago
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What does the atomic number of an element specify? what does the atomic number of an element specify?
GREYUIT [131]
The atomic number of an element identifies the number of protons and electrons.
8 0
3 years ago
Given the chemical equation: 2 Pb + O2 → 2 PbO, if 51.8 grams of Pb are formed in this reaction, then 8.00 grams of O2 must have
Nutka1998 [239]

Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

Molar mass of O2 = 32 g

Molar mass of PbO = 207 + 32 = 239 g

Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2

7 0
3 years ago
Two different compounds are obtained by combining nitrogen with oxygen. the first compound results from combining 46.7 g of n wi
kondaur [170]
<span>First:

46.7 g of N with 53.3 g of O,

=> mass ratio O to N = 53.3 / 46.7 = 1.1413

Second

17.9 g of N and 82.0 g of O.

mass ratio of O to N = 82.0 / 17.9 = 4.5810

Third

Ratio of the mass ratio of O to N in the second compound to the mass ratio of O to N in the first compound =

= 4.5810 / 1.1413 = 4.013 ≈ 4

Answer: 4
</span>
8 0
3 years ago
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