The gas sample consists of CH₄ and He.
Number of CH₄ moles - 4 g/ 16 g/mol = 0.25 mol
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
Therefore 0.25 mol of CH₄ gas occupies a volume of 22.4 L/mol x 0.25 mol
Volume of methane - 5.6 L
Number of He moles - 2.00 g/ 4 g/mol = 0.5 mol
Volume occupied by He - 22.4 L /mol x 0.5 mol = 11.2 L
The total volume of the sample = 5.6 L + 11.2 L = 16.8 L
Answer:
Average acceleration = - 2 m/s^2
Explanation: Have a nice day
Assuming that the number of mols are constant for both conditions:
Now you plug in the given values. V_1 is the unknown.
Separate V_1
V= 162.782608696 L
There are 2 sig figs
V= 160 L
The stability of atomic nuclei relies on the forces within the atom that balance out the charge. The electrons have the power to make an atom negatively or positively charged, but neutrons allow the atom to be electrically neutral regardless. The gravitational pull of protons and neutrons in the atomic nuclei keeps the electrons in an orbit, and with less protons than neutrons, electrons will be pulled into the nuclei and make the atom unstable; with less neutrons than protons, the electrons will be repelled and make the atom unstable. Therefore, the number and ratio of protons to neutrons are the factors that make an atom stable.
Answer: ratio of neutrons to protons and number of protons and neutrons
Hope this helps!
We will use the expression for freezing point depression ∆Tf
∆Tf = i Kf m
Since we know that the freezing point of water is 0 degree Celsius, temperature change ∆Tf is
∆Tf = 0C - (-3°C) = 3°C
and the van't Hoff Factor i is approximately equal to 2 since one molecule of KCl in aqueous solution will produce one K+ ion and one Cl- ion:
KCl → K+ + Cl-
Therefore, the molality m of the solution can be calculated as
3 = 2 * 1.86 * m
m = 3 / (2 * 1.86)
m = 0.80 molal
