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professor190 [17]
3 years ago
7

What phases would Venus show if the geocentric model were correct?

Physics
1 answer:
valina [46]3 years ago
4 0

Answer:

It would show - New, waxing crescent, waxing half, waxing gibbous, full, waning gibbous, waning half, waning crescent phases just like moon.

Explanation: Geocentric model also known as geocentrism, gives the description of universe with Earth at the center. It is often exemplified by the Ptolemaic system. Under this system all the planets, stars, moon and the sun orbited the Earth. Ptolemaic order of spheres from Earth outward is Moon, Mercury, Venus, Sun, Mars. Jupiter, Saturn, Fixed stars, Primum Mobile. It was replaced by the heliocentric model where sun is at the center.

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A .025 kg bullet is moving at 350 m/s when it hits and then passes through a 7 kg block of wood. After the bullet passes through
slamgirl [31]

Answer:

The final velocity of the wooden block is equal to 1.035 m/s

Explanation:

Given that mass of bullet = m_{b} = 0.025kg

                Mass of wood = m_{w} = 7kg

               Initial velocity of bullet = u_{b} = 350m/s

              Final velocity of bullet = v_{b} = 60m/s

               Initial velocity of wood = o

               Final velocity of wood = v_{w]

   Here momentum is conserved so initial momentum = final momentum

            m_{b}u_{b} = m_{b} v_{b} + m_{w}v_{w} .

    Upon substituting these values in above equation , we get

        v_{w} = 1.035m/s.

7 0
3 years ago
A constant amount of charge passes through a conductor. How is current affected if the same amount of charge passes in less time
baherus [9]

Answer:

B. The current increases.

Explanation:

As we know that rate of flow of charge through the conductor is known as electric current

So we have

i = \frac{q}{t}

here we know that charge Q flowing through the conductor is constant while the time in which it passes through it is decreased

so we can say that the ratio of charge and time will increase

so here we have

i = increased

So correct answer will be

B. The current increases.

4 0
3 years ago
A shot is fired at an angle of 60 degree horizontal with Kinetic energy E. If air resistance is ignored, the K.E at the top of t
Lapatulllka [165]
I'm not sure what "60 degree horizontal" means.

I'm going to assume that it means a direction aimed 60 degrees
above the horizon and 30 degrees below the zenith. 

Now, I'll answer the question that I have invented.

When the shot is fired with speed of 'S' in that direction,
the horizontal component of its velocity is    S cos(60)  =  0.5 S ,
and the vertical component is   S sin(60) = S√3/2  =  0.866 S .  (rounded)

-- 0.75 of its kinetic energy is due to its vertical velocity.
That much of its KE gets used up by climbing against gravity.

-- 0.25 of its kinetic energy is due to its horizontal velocity.
That doesn't change. 

-- So at the top of its trajectory, its KE is 0.25 of what it had originally. 

That's  E/4 .
3 0
2 years ago
I think you said everything but the answer.
jeka94

Answer:

What does that even mean?

Explanation:

7 0
2 years ago
Read 2 more answers
A mango is dropped and falls freely from rest. What are its position and velocity after
marissa [1.9K]

Answer:

1s^{2}

Explanation:

5 0
3 years ago
Read 2 more answers
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