The answer is 21m because the motion is in one dimension with constant acceleration.
The initial velocity is 0, because it started from rest, the acceleration <span>ax</span> is <span>4.7<span>m<span>s2</span></span></span>, and the time t is <span>3.0s</span>
Plugging in our known values, we have
<span>Δx=<span>(0)</span><span>(3.0s)</span>+<span>12</span><span>(4.7<span>m<span>s2</span></span>)</span><span><span>(3.0s)</span>2</span>=<span>21<span>m</span></span></span>
Explanation:
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C.) shaking a rope up and down
Answer:
The Tension in the cable is 392.3N. The vertical reaction at the hinge (fixed end) is 850.3N.
The tension in the cable was calculated using the principles of moments which states that the total sum of the clockwise moments is equal to the total sum of anticlockwise moments on a system in equilibrium.
Explanation:
Sum of Clockwise moments = Sum of anticlockwise moments
900×1 + 200×3 + 90×6 = T×Sin120 × 6
900 + 600 + 540 = 5.20T
T = 2040/5.20 = 392.3N
Summing vertical forces
R + Tsin120 = 900 +200+90
R + 392.3sin120 = 1190
R + 339.7 = 1190
R = 1190 - 339.7
R = 850.3N