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Gre4nikov [31]
2 years ago
7

A diver 50 m deep in 10∘C fresh water exhales a 1.0-cm-diameter bubble. What is the bubble's diameter just as it reaches the sur

face of the lake, where the water temperature is 20∘C?
Physics
1 answer:
aliya0001 [1]2 years ago
4 0

Answer:

18.2mm

Explanation:

D = 50m

T1 = 10+273 = 283K

T2 = 20+273 = 293K

R1 = 5x10^-3

Absolute pressure at 50m

P1 = pA + pwateer x g x d

= 101000+ 1000x9.81x50

= 591500pa

New volume of bubble

= P1v1/T1 = p2v2/T2

= 125x10^-9 x 591500x293/101000*283

= 757.9x10^-9m³

R2 = 9.2x10^-3

D2 = 18.2mm

Or 1.82cm

You might be interested in
Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. S
Alja [10]

Answer:

16294 rad/s

Explanation:

Given that

M(ns) = 2M(s), where

M(s) = 1.99*10^30 kg, so that

M(ns) = 3.98*10^30 kg

Again, R(ns) = 10 km

Using the law of gravitation, the force between the Neutron star and the sun is..

F = G.M(ns).M(s) / R²(ns), where

G = 6.67*10^-11, gravitational constant

Again, centripetal force of the neutron star is given as

F = M(ns).v² / R(ns)

Recall that v = wR(ns), so that

F = M(s).w².R(ns)

For a circular motion, it's been established that the centripetal force is equal to the gravitational force, hence

F = F

G.M(ns).M(s) / R²(ns) = M(s).w².R(ns)

Making W subject of formula, we have

w = √[{G.M(ns).M(s) / R²(ns)} / {M(s).R(ns)}]

w = √[{G.M(ns)} / {R³(ns)}]

w = √[(6.67*10^-11 * 3.98*10^30) / 10000³]

w = √[2.655*10^20 / 1*10^12]

w = √(2.655*10^8)

w = 16294 rad/s

7 0
3 years ago
the threshold of hearing is defined as the minimum discernible intensity of the sound. it is approximately 10−12w/m2 . find the
vivado [14]

The distance is 97720.5 m

From the question, we have

P = 0.06 W × 2 = 0.12 W

d = ?

Sound intensity, I = P/4πd²

I = 10⁻¹² W/m²

10⁻¹² = 0.12/4πd²

d = 97720.5 m

The distance is 97720.5 m

Sound intensity :

The power carried by sound waves per unit area in the direction  perpendicular to that region is known as sound intensity or acoustic intensity. The watt per square meter (W/m2) is the SI unit of intensity, which also covers sound intensity. Sound intensity is a measure of how quickly energy moves across a given space. The unit area in the SI measurement system is 1 m2. So Watts per square meter are used to measure sound intensity. As there will be energy flow in certain directions but not in others, sound intensity also provides a measure of direction.

To learn more about Sound intensity visit: brainly.com/question/12899113

#SPJ4

3 0
1 year ago
Suppose a woman raises a 65 N object in 2m in 4 seconds.
Novosadov [1.4K]

Answer:

\huge\boxed{\sf P.E = 130\ Joules}

\huge\boxed{\sf P = 32.5\ Watts}

Explanation:

<u>Given Data:</u>

Weight = W = 65 N

Height = h = 2 m

Time = t = 4 secs

<u>Required:</u>

Power = P = ?

Work Done in the form of Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = Wh

P = P.E. / t

<u>Solution:</u>

P.E. = (65)(2)

P.E = 130 Joules

P = P.E. / t

P = 130 / 4

P = 32.5 Watts

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807 </h3>
8 0
2 years ago
What force is needed to give a 4.5-kg bowling ball an acceleration of 9 m/s2?
Mrac [35]
The correct answer is 40.5 Newtons just finished the quiz and 36.5 was incorrect.
7 0
3 years ago
Read 2 more answers
Why does a balloon filled with the air from your lungs sink to the ground but a balloon filled with Helium floats ?
hoa [83]

Helium is lighter than air from the lungs.

Explanation:

A balloon filled with the air from lungs will sink to the ground but a balloon filled with Helium floats because helium is lighter than air.

Air is a mixture of many gases.

The air from the lungs is predominantly made up of carbon dioxide and water vapor.

  • Gram per mole of carbon dioxide is 44. Water vapor is 18.
  • Compared to helium which is 4, we see that the gas is lighter.
  • Since the gas is lighter, it will float in air.
  • The main component of air around us is nitrogen gas with a gram per mole of 28.
  • A balloon filled with more of air from the lungs weigh more than that will filled air around and even far more than helium gas.
  • This will cause a helium filled balloon to float.

learn more:

Density brainly.com/question/1698555

#learnwithBrainly

4 0
3 years ago
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