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3 years ago

In degrees celsius, the boiling point of water is ___ degrees higher than the freezing point. (Apex)

Chemistry

2 answers:

love history [14]3 years ago

8 0

Explanation:

Freezing point is defined as the point at which a liquid changes into solid state. On the other hand, boiling point is defined as the point at which liquid state of a substance starts to convert into vapors or gaseous state.

It is known that freezing point of water is zero degree celsius or 273 K. Whereas boiling point of water is 100 degree celsius or 373 K.

Hence, we can conclude that in degrees celsius, the boiling point of water is 100 degrees higher than the freezing point.

mixer [17]3 years ago

5 0

The freezing point of water in Celsius is 0 degrees and the boiling point is 100 degrees so the answer would be 100 degrees

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Which one of the following best represents the predicted approximate chemical shift and coupling for the hydrogen(s) indicated w

melomori [17]

Answer:

The answer is quartet 2.40 ppm.

Note: Kindly find an attached image below for the part of the solution to this question

Sources: The image was researched from Course hero platform

Explanation:

Solution

Multiplicity or (n+1) rule:

It helps in determination of multiplicity of an individual proton or individual types of proton which are available in the molecule.

Multiplicity =(n+1)

Thus

The non equivalent protons which are attached from adjacent atom is denoted by n.

Now because there are three non-equivalent protons are present at adjacent carbon of methylene group, hence the multiplicity of methylene hydrogen is given as follows:

The multiplicity will be the same for the two hydrogen's. thus we compute multiplicity only for one hydrogen atom stated below:

Non- equivalent = 3

Multiplicity = (3 +1)

= 4

= Quartet for 2H

A quartet for 2H indicates that the hydrogen atoms attached from the carbon, which is attached one side from a methyl group and the other side form an atom that have no any hydrogens.

Now due +I effect of carbonyl group, chemical shift value is high for these two hydrogens which is exactly at 2.40 ppm or 2.40 Quartet.

5 0

3 years ago

CH3OH can be synthesized by the following reaction.

puteri [66]

Answer:

A: There is 43.12 Liter of H2 needed

B: There is 21.56 liter of CO needed

Explanation:

Step 1: Data given

CO(g)+2H2(g)?CH3OH(g)

For 1 mol of CO consumed, we need 2 moles of H2 to produce 1 mol of CH3OH

Molar mass of CO = 28.01 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass of CH3OH = 32.04 g/mol

Step 2: What volume of H2 gas (in L), measured at 754mmHg and 90?C, is required to synthesize 23.0g CH3OH?

Pressure = 754 mmHg = 0.992 atm

Temperature = 90°C = 363 Kelvin

mass of CH3OH produced = 23.0 grams

Step 3: Calculate moles of CH3OH

Moles CH3OH = mass CH3OH / Molar mass CH3OH

Moles CH3OH = 23.0 grams / 32.04 g/mol

Moles CH3OH = 0.718 moles

Step 4: Calculate moles of H2

For 1 mol of CO consumed, we need 2 moles of H2 to produce 1 mol of CH3OH

For 0.718 moles CH3OH produced, we have 2*0.718 moles =1.436 moles of H2 and 0.718 moles of CO

Step 5: Calculate volume of H2

p*V = n*R*T

with p = the pressure = 0.992 atm

with V the volume = TO BE DETERMINED

with n = the number of moles = 1.436 moles H2

with R = the gasconstant = 0.08206 L*atm/ K*mol

with T = the temperature = 363 Kelvin

V = (n*R*T)/p

V = (1.436*0.08206*363)/0.992

V = 43.12 L

Step 6: Calculate volume of CO

p*V = n*R*T

with p = the pressure = 0.992 atm

with V the volume = TO BE DETERMINED

with n = the number of moles = 0.718 moles CO

with R = the gasconstant = 0.08206 L*atm/ K*mol

with T = the temperature = 363 Kelvin

V = (n*R*T)/p

V = (0.718*0.08206*363)/0.992

V = 21.56 L

A: There is 43.12 Liter of H2 needed

B: There is 21.56 liter of CO needed

3 0

3 years ago

Please help! It’s due today. I’ll give brainliest

MArishka [77]

Answer:

look at it is the correct answer because if a new gas has formed bubbles will how or change of colour so look at it

Explanation:

5 0

3 years ago

Read 2 more answers

Question is in picture! Due at 3:45!!!

olga nikolaevna [1]

The answer is D.2HCl

6 0

3 years ago

If 4.5 moles of AlCl3 were made, how many moles of CuCl2 were used?

Troyanec [42]

Answer:

6.75 moles of CuCl₂ were used

Explanation:

Given data:

Number of moles of AlCl₃ formed = 4.5 mol

Number of moles of CuCl₂ used = ?

Solution:

Chemical equation:

3CuCl₂ + 2Al → 2AlCl₃ + 3Cu

Now we will compare the moles of CuCl₂ and AlCl₃

AlCl₃ : CuCl₂

2 : 3

4.5 : 3/2×4.5 = 6.75

6.75 moles of CuCl₂ were used.

7 0

2 years ago