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almond37 [142]
4 years ago
14

Which of the following is the shape of a cross-section of the figure shown

Mathematics
1 answer:
Slav-nsk [51]4 years ago
7 0
C

pentagram cause it’s a pentagonal prism
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In the following triangle theta=60.Find the values of the angles of the angles B and B'
Contact [7]

Answer:

180-60 = 120 if triangle is not equilateral it cannot be isosceles then depending where the angles are they will show  60,60,60 if equilateral

For isosceles it would need to be 58 61 61 as 60, 60,60 cannot be isosceles.

Vectors 60 if right angled triangle = 90-60 = 30

So angles = 30 and 90 degree or just 120 if angle theta is a vector as explained below.

Step-by-step explanation:

Statement: If two vectors are represented by the sides of a triangle both in magnitude and direction taken in order, the resultant sum of the vectors is given by the closing third side of the triangle taken in the reverse order both in the magnitude and direction

5 0
3 years ago
A bottle of hand lotion is on sale for $2.25. If this price represents a 50% discount from the original price,what is the origin
nalin [4]

Step-by-step explanation:

50% is basically half. So if you double the price ($2.25) x 2 you will have your answer.

So the answer is $4.50..!

3 0
3 years ago
Is negative twelve a whole number,integer,or rational number?
mrs_skeptik [129]
Its an Integer. Integers include negative numbers, zero and positive numbers :)
8 0
3 years ago
Read 2 more answers
875 rounded to nearest ten
velikii [3]
880
Underline the number in the tens place
look to the right
if number is greater than 5
add 1 to the underlined number
leave the numbers behind the underlined number zero
4 0
3 years ago
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The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr
aniked [119]

Answer:

(a) E(X) =  0.383

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) P(x = 4) = 0.000169

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$ E(X) =  \frac{n \times r}{N} $

$ E(X) =  \frac{10 \times 8}{209} $

$ E(X) =  \frac{80}{209} $

E(X) =  0.383

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$ P(x = 4) =  \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}} $

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$ P(x = 4) =  \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{70 \times 84944276340}{35216131179263320}

P(x = 4) = 0.000169

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0
3 years ago
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