Answer:
As you go down group 1, the number of electron shells increases – lithium has two, sodium has three, and so forth. The attraction from the positive nucleus to the negative electron is less. This makes it easier to remove the electron and makes the atom more reactive.
Answer: the employment rate will go down and more people will be more lazy
Explanation:...
Answer:
See explanation
Explanation:
Heat of formation, also called standard heat of formation, enthalpy of formation, or standard enthalpy of formation, the amount of heat absorbed or evolved when one mole of a compound is formed from its constituent elements, each substance being in its normal physical state (gas, liquid, or solid)(Encyclopedia Britannica).
The greater the magnitude of the negative value of the heat of formation(the more negative), the greater stability of the compound formed. Hence, a more negative heat of formation (a larger negative number) means that a compound is more stable than an isomer with a less negative heat of formation.
Answer:
The given reaction in your problem is the ionic equation for an acid (carbonic acid) reacting with a base (sodium hydroxide). All components of the reaction are then written in ionic form except for reactant weak electrolytes and the driving force product compound of the reaction (H2O). See following explanation.
Explanation:
Metathesis Rxn: molecular equation of rxn
H₂CO₃(aq) + 2NaOH(aq) => Na₂CO₃(aq) + 2H₂O(l)
Ionic Equation: shows all components of the reaction
H₂CO₃(aq) + 2Na⁺(aq) + 2OH⁻(aq) => 2Na⁺(aq) + CO₃²⁻(aq) + 2H₂O(l)
H₂CO₃(aq) wk. electrolyte and H₂O(l) driving force compound are not shown ionized in ionic equation. Only strong electrolytes that ionize 100%; i.e., salts and strong acids and bases.
Net Ionic Equation: shows only the reactive components without the spectator ions (nonreactive components), in this case, the Na⁺(aq) ions.
H₂CO₃(aq) + 2OH⁻(aq) => CO₃²⁻(aq) + 2H₂O(l)
