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Stella [2.4K]
3 years ago
6

Will a crayon dissolve in water?

Chemistry
2 answers:
sweet-ann [11.9K]3 years ago
6 0

Answer:

Yes

Explanation:Like wax crayons but they can dissolve in water.

erma4kov [3.2K]3 years ago
3 0

Answer:

<h2>here you go :)</h2>

Explanation:

Two variations on watercolor pencils available are woodless pencils (just the pencil 'lead' with a paper wrapper) and water-soluble crayons (like wax crayons, but they dissolve in water). Water-soluble crayons enable you to put down more pigment (or color) faster than a watercolor pencil, as they're softer and broader.

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Calculate the theoretical yield of 1-bromobutane; base your calculations on using 1.0 g of 1-butanol (as the limiting reagent).
Tomtit [17]

C₄H₉OH + HBr = C₄H₉Br + H2O

Δmole of alcohol gives 1 mole of bromobutanol

HBr is in excess, so the yield of the product is limited by the alcohol

Wt. of 1 butanol = 18

Molar mass of the butanol = 74.12 g/mole

Moles of the alcohol = 1/74.12 = 0.01349 moles

So, moles of bromobutane = 0.01349 moles

Molar mass of C₄H₉Br = 137.018 g/moles

So, theoretical mass of bromobutane is = 0.01349 × 137.0.18

= 1.85 g


6 0
3 years ago
Read 2 more answers
A nuclide of phosphorus 3015P decays into a nuclide of silicon 3014Si. In order to satisfy charge conservation and lepton number
jeka94

In order to satisfy charge conservation and lepton number conservation the other products must be neutron.

<h3>What is conservation of mass?</h3>

The principle of conservation of mass states that, the sum of the initial mass of reactants must be equal to final mass of the products.

_{15}^{30}P\ --- > \ _{14}^{30} Si \ + \ ^{0}_{1} n

The balanced reaction of radioactive decay of phosphorous shows conservation of mass.

Thus, in order to satisfy charge conservation and lepton number conservation the other products must be neutron.

Learn more about radioactive decay here: brainly.com/question/1383030

#SPJ1

3 0
1 year ago
What accounts for the large increase in volume when sugar burns?
Dimas [21]
I don’t know type it up yourself
8 0
3 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction:P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°
miskamm [114]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1835 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)    \Delta H_1=157kJ   ( × 4)

(2) P_4(g)+6Cl_2(g)\rightarrow 4PCl_3(g)     \Delta H_2=-1207kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[4\times (-\Delta H_1)]+[1\times \Delta H_2]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(4\times (-157))+(1\times (-1207))=-1835kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1835 kJ.

6 0
3 years ago
5. Extend your thinking: What strategies did you use to hunt for moths?
Sonja [21]
Answer: There are many strategies used to hunt and kill moths. I’ll tell you my way of hunting and killing moths.

Step-By-Step Explanation:
Morning and Afternoon: First, get a sticky trap. You can get it at Target or Walmart. Cover it with moth pheromones or anything you know that can attract the moths. The sticky trap, will stick them to the trap and will eventually die after no being able to escape for a long time.
Nighttime: Buy or Get a lamp and turn it on. This will attract lots of moths and it will help you see them. Then, spray insecticide or insect repellent at the. Lastly, they should die.
Tip: If things get too out of hand with a huge swarm of moths, then call pest control and they will surely get rid of them for you!
8 0
3 years ago
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