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Stella [2.4K]
3 years ago
6

Will a crayon dissolve in water?

Chemistry
2 answers:
sweet-ann [11.9K]3 years ago
6 0

Answer:

Yes

Explanation:Like wax crayons but they can dissolve in water.

erma4kov [3.2K]3 years ago
3 0

Answer:

<h2>here you go :)</h2>

Explanation:

Two variations on watercolor pencils available are woodless pencils (just the pencil 'lead' with a paper wrapper) and water-soluble crayons (like wax crayons, but they dissolve in water). Water-soluble crayons enable you to put down more pigment (or color) faster than a watercolor pencil, as they're softer and broader.

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GenaCL600 [577]

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not sure if this is the right way to answer this question but PbS is Phosphate-buffered saline (i think)

Explanation:

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A 155 g sample of an unknown substance was heated from 25°c to 40°c. in the process, the substance absorbed 569 calories of ener
Tasya [4]
Energy= 2381 joules
heat= Mass(kg) *change in temperature(K) * Cp
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Herbie left his house at 3:30 p.m. and arrived at Kit’s house at 5:00 p.m. The two boys live 7 miles apart. What was Herbie’s av
Kisachek [45]

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose they take t minutes to meet each other.

Distance covered by first friend in t minutes, = 0.2 *t=0.2∗t

Distance covered by second friend in t minutes , =0.15 *t=0.15∗t

Total distance is given as 7, so

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SO. the average speed is 10m: Answer

5 0
3 years ago
What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M
Fed [463]

<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>

What is benzoic acid found in?

  • Some natural sources of benzoic acid include: ​Fruits:​ Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
  • ​Spices:​ Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 =  0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

pH = pKa + log\frac{base}{acid}

4.2 + log\frac{0.05}{0.045} = 4.245

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

pH = pKa + log\frac{base}{acid}

4.245 = 3.75 + log\frac{base}{acid}

log\frac{base}{acid} = 0.5

\frac{base}{acid} = 3.162

Now we must solve the equation above. This will be done using the following values

\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

brainly.com/question/24052816

#SPJ4

3 0
1 year ago
Which is heavier einsteinium (Es) or europium (Eu)
SVETLANKA909090 [29]

I think the answer is einsteinium is the heavier one here.

8 0
3 years ago
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