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Shkiper50 [21]
3 years ago
15

A car accelerates down a level highway. What is the force in the direction of motion that accelerates the car?

Physics
1 answer:
Marina86 [1]3 years ago
8 0

Answer: The force of reaction force of the ground accelerates the car on a level road.

Explanation:

When the wheels apply tractive force on the wheels by applying torque that is generated by engine  of the car, the wheels in contact with the road tend to move backwards at the point of contact thus exerting a force in the direction opposite to the motion of the car. Now according to Newton's third law an equal and opposite forces act on the car which tend to accelerate the car in the direction of motion.

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Write a collision scenario here. If you choose your own collision, you can have neither, one, or both of the objects break. Be s
OleMash [197]

Answer:

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And it hits a steel guardrail and the car smashes in at the front and the guardrail is only bent while the car has the bumper and the hood along with the headlights and windshield along with the passenger side window break.

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3 years ago
The image of an object formed by plane mirror is​
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3 years ago
A square plate of side 9 m is submerged in water at an incline of 60∘ with the horizontal. Its top edge is located at the surfac
Tpy6a [65]

Answer:

The force on one side of  the plate is 3093529.3 N.

Explanation:

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y=\dfrac{\Delta y}{\sin60}

y=\dfrac{2\Delta y}{\sqrt{3}}

The area of strip is

dA=\dfrac{9\times2\Delta y}{\sqrt{3}}

We need to calculate the force on  one side of  the plate

Using formula of pressure

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dF=P\times dA

On integrating

\int{dF}=\int_{0}^{9\sin60}{\rho g\times y\times 6\sqrt{3}dy}

F=9800\times6\sqrt{3}(\dfrac{y^2}{2})_{0}^{9\sin60}

F=9800\times6\sqrt{3}\times(\dfrac{(9\sin60)^2}{2})

F=3093529.3\ N

Hence, The force on one side of  the plate is 3093529.3 N.

7 0
4 years ago
a stone is projected vertically up from the top of a tower 73.5m with velocity 24.5 m/s . find the time taken by the stone to re
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The stone's altitude at time t is given by

y=73.5\,\mathrm m+\left(24.5\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2

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0=73.5\,\mathrm m+\left(24.5\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2\implies t=7.11\,\rm s

6 0
3 years ago
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