Answer:
The temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C
Explanation:
Here we make use of the Clausius-Clapeyron equation;
Where:
P₁ = 1 atm =The substance vapor pressure at temperature T₁ = 282°C = 555.15 K
P₂ = 0.2 atm = The substance vapor pressure at temperature T₂
= The heat of vaporization = 28.5 kJ/mol
R = The universal gas constant = 8.314 J/K·mol
Plugging in the above values in the Clausius-Clapeyron equation, we have;
T₂ = 440.37 K
To convert to Celsius degree temperature, we subtract 273.15 as follows
T₂ in °C = 440.37 - 273.15 = 167.22 °C
Therefore, the temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C.
Answer;
Molar mass of water is 18.02 g/mol
Explanation;
-Molar mass of a compound is determined by adding the relative atomic mass of each atom present in the compound. Molar mass of one mole of a compound, it is the weight in grams of 6.02 × 1023 atoms or molecules.
-Therefore; to calculate the molar mass of Water (H2O); we first know the RAM of hydrogen and oxygen which are; H=1.01 and O= 16.00
Since there is two atom of hydrogen and one atom of oxygen in water;
Then; the Molar mass of water will be; 2×1.01 + 1 ×16 = 18.02 g/mol
Its probably just gacl, that's the short version atleast
If we r talking about the whole atom, we would see that the atom have higher number of protons (positive charges)than electrons (negative charges). That means the number of positiv charges are dominating over the number of negative charges which makes the atom a positiv charges atom
