Answer:
D) Joe need to walk 481 m in a direction 40.9° north of east
Explanation:
Given:
1. Walk 300 m north
2. Walk 400 m northwest
3. Walk 700 m east-southeast and the treasure is buried there
Taking north as positive y axis and east as positive x axis.
Resolving their positions into x and y vector components.
1. d1 = 300j
2. d2 = -400cos45i + 400sin45j
3 d3 = 700cos22.5i - 700sin22.5j
Resultant position.
d = d1+d2+d3
d = (-400cos45 + 700cos22.5)i + (300+400sin45-700sin22.5)j
d = (363.873)i + (314.964)j
D = √( (363.873)^2 + (314.964)^2)
D =481.25m ~= 481m
Angle = taninverse (314.964/363.873)
Angle = 40.9°
Since the x and y components are both positive, it implies that their position is north of east
Therefore, Joe need to walk 481 m in a direction 40.9° north of east
Answer:
E) V=(m/M)v
Explanation:
Given that
Mass of the small ball = m
Initial velocity of the small ball = v
Mass of the larger ball = m
Initial velocity of the larger ball = 0
After the collision
The velocity of the small ball = 0
The velocity of the larger ball = V
There is no any external force that is why linear momentum will be conserve.
From linear momentum conservation
Pi=Pf
m v + M x 0 = m x 0 + M V
m v +0 = 0 + M V
Therefore the answer will be E.
E) V=(m/M)v
1000 m/s
You have the wavelength and frequency, you just need to solve for velocity. You can do this by multiplying each side of the equation by frequency.
Explanation:
It is given that,
Total mass is 70 kg
The truck exerts a constant force of 20 N.
Then the net force is given by :
F = ma
a is acceleration of rider
Initial velocity of rider is 0. So, using equation of kinematics to find the final velocity as :
Since, 1 m/s = 2.23 mph
4.28 m/s = 9.57 mph
So, the speed of the rider is 4.28 m/s or 9.57 mph.
Ohm's Law<span> deals with the relationship between voltage and current in an ideal conductor. </span>Ohm's law<span> states that the current through a conductor between two points is directly proportional to the voltage across the two points. </span>