Ask question

Ask question

All categories

3 years ago

6

If I leave a cinema at 12.00am and arrive at 12.00pm how many hours are that.

1 answer:

spayn [35]3 years ago

5 0

Answer:

a.12 hours

Step-by-step explanation:

12 am (00:00) represents midnight and 12 pm is noon (pm represents noon - after noon)so the time passes between 12 am to 12 pm is 12 hours

You might be interested in

Identify the slope and Y- intercept of the graph of the equation. Then graph the equation. Y =-5/4x + 1

lbvjy [14]

Well the slope would be m=-5/4 and the y-intercept would be 1 because of y=mx+b

3 0

3 years ago

Kiara has $20 to spend.She wants to buy a book for $12 and spend the remaining money on name tags for he luggage.Each name tag c

Finger [1]

The answer is

C) 2x + 12 < 20

3 0

4 years ago

Read 2 more answers

What’s the answer to this one! 15 points!

Phoenix [80]

Answer:

D

Step-by-step explanation:

Because they are opposite of each other

5 0

3 years ago

Read 2 more answers

Solve this equation: 80 = 3y + 2y + 4 + 1.

Verdich [7]

Let us first write down the given equation.
80 = 3y + 2y + 4 + 1
80 = 5y + 5
80 - 5 = 5y
75 = 5y
Just reversing both sides we get
5y = 75
Now dividing both sides by 5 we get
y = 15
So the value of y is 15. I hope the procedure for solving the problem is clear to you. In future you can solve such problems with ease following the procedure described.

6 0

3 years ago

Read 2 more answers

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$

$\sigma = \sqrt{4996.78}$

$\sigma = 70.69$ --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

$c =0.95$

So:

$\alpha = 1 -c$

$\alpha = 1 -0.95$

$\alpha = 0.05$

Calculate the degree of freedom (df)

$df = n -1$

$df = 20 -1$

$df = 19$

Determine the critical value at row $df = 19$ and columns $\frac{\alpha}{2}$ and $1 -\frac{\alpha}{2}$

So, we have:

$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

$X^2_{0.975} = 8.907$ --- at $1 -\frac{\alpha}{2}$

So, the confidence interval of the standard deviation is:

$\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }$ to $\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }$

$70.69 * \sqrt{\frac{20 - 1}{32.852}$ to $70.69 * \sqrt{\frac{20 - 1}{8.907}$

$70.69 * \sqrt{\frac{19}{32.852}$ to $70.69 * \sqrt{\frac{19}{8.907}$

$53.76$ to $103.25$

8 0

3 years ago