Answer : The value of equilibrium constant (K) is, 424.3
Explanation : Given,
Concentration of
at equilibrium = 0.067 mol
Concentration of
at equilibrium = 0.021 mol
Concentration of
at equilibrium = 0.040 mol
The given chemical reaction is:
![CO+2H_2\rightarrow CH_3OH](https://tex.z-dn.net/?f=CO%2B2H_2%5Crightarrow%20CH_3OH)
The expression for equilibrium constant is:
![K_c=\frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
Now put all the given values in this expression, we get:
![K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%280.040%29%7D%7B%280.021%29%5Ctimes%20%280.067%29%5E2%7D)
![K_c=424.3](https://tex.z-dn.net/?f=K_c%3D424.3)
Thus, the value of equilibrium constant (K) is, 424.3
The temperature of the gas is proportional to the average kinetic energy of its molecules. Faster moving particles will collide with the container walls more frequently and with greater force. This causes the force on the walls of the container to increase and so the pressure increases.
<span>The water soaks in the cracks of rocks, freezes and expands breaking the rock apart.</span>
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