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otez555 [7]
3 years ago
9

In figures (a)-(d), a block moves to the right in the positive x direction through the displacement Δx while under the influence

of a force with the same magnitude F. Which of the following is the correct order of the amount of work done by the force F, from most positive to most negative? d > c > a > b c > a > d > b c > a > b > d
Physics
1 answer:
Elena L [17]3 years ago
5 0

-------ca>a>b>s---c>a>d>b©©s>c>a>b

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3 years ago
The minimum stopping distance of a car moving at 20.5 mi/h is 11.6 m. Under the same conditions (so that the maximum braking for
pshichka [43]

Answer:

d = 69 .57 meter

Explanation:

First case

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distance ( d ) = 11.6 meter                                       ( m = mass of the car )

Work done = 0.5 m v²  = 0.5 * 9.164² * m J  = 41.99 m J

Force = ( workdone /distance ) = ( 41.99 m / 11.6 )   =  3.619 m N

Second case

v = 50.2 mi/h = 22.44135 m/s

d = ?

Work done = 0.5 * 22.44² * m J = 251.7768 * m J

Since the braking force remains the same .

3.619 m = ( 251.7768 m / d )

d = 69 .57 meter

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3 years ago
Joaquin has hockey practice at the same ice rink where Alton has curling practice. One day, they were both playing on the ice wi
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the puck recoils in each case.

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Read 2 more answers
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