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2 years ago

If a person runs 720m/minute for 15 minutes, how far will the person run?

Physics

1 answer:

julsineya [31]2 years ago

3 0

Answer:

10800

Explanation:

if someone runs 720 miles every minutes they will run 10,800 miles in 15 minutes

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Golf cart is the answer

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3 years ago

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Ten identical steel wires have equal lengths L and equal "spring constants" k. The wires are connected end to end so that the re

lapo4ka [179]

Answer:

$K_{system} = \frac{k}{10}$

Explanation:

When the springs are connected end to end, it means they are connected in series. When the springs are connected in series, the stress applied to the system gets applied to each of the springs without any change in magnitude while the strain of the system is the sum total of strains of each spring. The spring constant of the resultant system is given as,

$\frac{1}{K_{system}} = (\frac{1}{K_{1}})+(\frac{1}{K_{2}})+(\frac{1}{K_{3}})+ (\frac{1}{K_{4}})+.....+(\frac{1}{K_{n}})$

Here, n = 10

Spring constant of each spring = k

Thus,

$\frac{1}{K_{system}} = (\frac{1}{K_{1}})+(\frac{1}{K_{2}})+(\frac{1}{K_{3}})+ (\frac{1}{K_{4}})+.....+(\frac{1}{K_{10}})$

$\frac{1}{K_{system}} = (\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})$

$\frac{1}{K_{system}} = \frac{10}{k}$

$K_{system} = \frac{k}{10}$

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3 years ago

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A skydiver jumps out of a plane and immediately begins falling toward the Earth.

worty [1.4K]

Answer:

5.2m/s^2

Explanation:

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

$Vf=Vo+a.t (1)\\{Vf^{2}-Vo^2}/{2.a} =X(2)\\X= VoT+0.5at^{2} (3)\\X=(Vf+Vo)T/2 (4)$

Where

Vf = final speed

Vo = Initial speed

T = time

A = acceleration

X = displacement

In conclusion to solve any problem related to a body that moves with constant acceleration we use the 4 above equations and use algebra to solve

for this case we can use the ecuation number 3

x=100m

t=6.2s

Vo=0m/s

$X= VoT+0.5at^{2}\\X= 0.5at^{2}\\a=\frac{X}{0.5t^2} \\a=\frac{100}{0.5(6.2)^2}=5.2m/s^2$

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3 years ago

The magnetic domains in an iron nail are randomized unless it is placed in a magnetic field.

UNO [17]

Answer:

True plz thank me this is the answer

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2 years ago

IP A spark plug in a car has electrodes separated by a gap of 6.5×10−2 in . To create a spark and ignite the air-fuel mixture in

emmainna [20.7K]

Answer:

a.) $V=5283.2 \ V$

b.) $V=4064\ V$

Explanation:

<u>Electric Field and Potential Difference</u>

There are several conditions that must be met for a spark to be created into an air gap. Once the physical conditions are fixed, a minimum electric field is necessary for the spark to be initiated. Let s be the separation between the electrodes and V their potential difference. The electric field is

a.)

$\displaystyle E=\frac{V}{s}$

Solving for V

$V=E.s$

The separation is

$s= 5.5\cdot 10^{-2}\ in=0.001651 \ m$

Thus the potential difference is

$V=3.2\cdot 10^{6}\ V/m\times 0.001651 \ m$

$V=5283.2 \ V$

b.) If the separation was greater, the applied voltage needs to be greater if the electric field has to be constant. One possible measure to keep electrodes as close as possible is to build them as sharp edges. It gives the spark an easier path to travel to.

If the separation is 0.05 inches =0.00127 m

$V=3.2\cdot 10^{6}\ V/m\times 0.00127 \ m$

$V=4064\ V$

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3 years ago