The reaction between Magnesium and Hydrogen Chloride is:
Mg + 2 HCl → MgCl₂ + H₂
The balloon will inflate because gas is liberated in the presence of H₂.
Let's compute which of the reactants is limiting. The solution is as follows:
Molar mass of Mg = 24.305 g/mol
Molar mass of HCl = 36.45 g/mol
Flask A:
Moles HCl needed = 7.23 g Mg*(1 mol/24.305 g)*(2 mol HCl/1 mol Mg) = 0.595 moles
Since the available mass of Mg needs 0.595 moles of HCl, and HCl has excess amounts of 1.05 moles, the excess reactant is HCl and the limiting reactant is Mg. So, let's base our production on Mg. The more H₂ produced, the bigger the balloon.
Flask A:
Moles H₂ produced = 7.23 g Mg*(1 mol/24.305 g)*(1 mol H₂/1 mol Mg) = 0.297 moles
Flask B:
Moles H₂ produced = 1.22 g Mg*(1 mol/24.305 g)*(1 mol H₂/1 mol Mg) = 0.05 moles
Therefore, Flask A will inflate the most.
Answer:
D
Explanation:
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Lithium dihydrogen phosphate
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Explanation:
Answer:
[AB] is 0.65 M
Explanation:
Let the concentration of AB after 10.3s be y
Rate = ky^2 = change in concentration of AB/time
k = 0.2 L/mol.s.
Change in concentration of AB = 1.5 - y
Time = 10.3s
0.2y^2 = 1.5-y/10.3
0.2y^2 × 10.3 = 1.5 - y
2.06y^2 = 1.5 - y
2.06y^2 + y - 1.5 = 0
The value of y must be positive and is obtained using the quadratic formula
y = [-1 + sqrt(1^2 -4×2.06×-1.5)]/2(2.06) = [-1 + sqrt(13.36)]/4.12 = 2.66/4.12 = 0.65 M