The germ theory of disease
eventually led to the development of certain types of vaccines. This theory explains
that specific type or types of microorganisms, which are bacteria, virus, fungi,
or protest species, cause some diseases. These organisms can enter the human
body, and can even grow and reproduce, causing infection, inflammation to
specific organs in the body, and others. One particular vaccine developed successfully
through this understanding is the smallpox vaccine, which is an important
vaccine up to this day.
Answer:
1. Diazonium salt
2. Coupling component
Explanation:
Azo dyes re synthesized by the combination of two organic compounds viz
1. Diazonium salt
2. Coupling component
1) For methyl red, the diazonium salt which is an intermediate product is produced by the reaction of hydrochloric acid (HCL) with anthranilic acid and sodium nitrate (NaNO₂)
2) The produced diazonium salt is then combined with dimethylaniline which is a coupling component rich in electrons to undergo a chemical reaction that by an aromatic substitution mechanism to produce methyl red as the final product.
A chemical reaction (signs)
- rusting
- change in base of chemical
- for example lets say u mix two chemicals, and then it becomes a different new chemical (it changed from the inside)
a physical
- a physical reaction is outer looks not inside.
- it changes on the outside, like changing a color
Answer:
Explanation:
(a) Convert pounds to kilograms.
(b) Calculate the dose
Answer:
Explanation:
To find the theoretical yield of the equation. First identify the limiting reactant in a chemical equation.
Step 1: write out the equation and balance it.
Al+ 3mno2=3mn+ 2Alo3.
The limiting reactant is mn02 because it is not found in excess.
Step 2: convert the % to gram . All contain 67.2% mole and mno2 will be 100-67.2= 32.8
All=67.2÷100×290(total gram of the reactants)=194.88g
Mno2=32.8÷100×290g=94.12g.
Step 3:calculate the molar mass of mno2 and that of mn. The atomic mass of mn is 54.9380 and that of oxygen is 16.
Mno2=54.938+ (16)2=86.98g/mol.
Mn=54.938.
Step 4:
From your balanced equation , calculate mn.
94.12g mno2× (1mol mno2÷86.98(molarmass) of mno2×3 mol of mn/4molAl×54.938g of mn÷1mol of mn.
94.12g×1÷86.98g×3÷4×54.938÷1
=44.58g
