The heat that is needed to raise the temperature of 78.4 g of aluminium from 19.4 °c to 98.6°c is 5600.77 j
<u><em>calculation</em></u>
Heat(Q) = mass(M) x specific heat capacity (C) x change in temperature(ΔT)
where;
Q=?
M = 78. 4 g
C=0.902 j/g/c
ΔT=98.6°c -19.4°c =79.2°c
Q is therefore = 78.4 g x 0.902 j/g/c x 79.2°c =5600.77 j
Answer: THE ANSWER IS D
Explanation:
an alcohol is a hydrocarbon chain with an hydroxyl group (OH)
A, B, AND C ARE ALL ALCOHOLS, SO THE ANSWER IS D
The right subject for this question is physics.
To calculate the work you use the formula:
Work = force * displacement
Work = 2500 pounds * 30 feet = 75,000 pounds - feet
To calculate the power you use the formula:
power = work / time
Power = 75,000 pound - feet / 30 seconds = 2300 pound-feet / second.
Answer:
mass= 14kg
Explanation:
density= mass/volume
so that means mass= volume x density
m= 2kg/m³ x 7m³
m= 14 kg
Hope this helps
Answer:
13.33 g/dm³
Explanation:
Concentration (g/dm³)= mass(g) ÷ volume (dm³)
Now you need to convert 150 cm³ to dm³
1000cm³ = 1 dm³
thus, 150 cm3= 150 ÷ 1000
= 15dm³
and you already have mass in grams
so concentration = 2 ÷ 0.15
= 13.33 g/dm³ and there you go.. solved ;)
