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ruslelena [56]
3 years ago
6

When describing electromagnetic radiation, there is a(n) _____________ relationship between wavelength and frequency and the gre

ater the frequency, the ____________ energy the electromagnetic radiation has.
A) direct; less

B) direct; more

C) inverse; more

D) inverse; less

Physics
2 answers:
Natalija [7]3 years ago
8 0

Answer: C. Inverse; more

Explanation:

An electromagnetic radiation can be described by it wavelength or frequency or energy. These are related by:

c = λ f

where, c is the speed of light, λ is the wavelength of the light and f is the frequency.

E = h f

where E is the energy, h is Planck's constant and f is the frequency.

Thus, there is inverse relation between wavelength and frequency. As speed of light is constant in a given medium, with increase in frequency, wavelength decreases.

There is direct relationship between energy and frequency.

When frequency increases, Energy increases. Thus, greater the frequency, greater energy the electromagnetic radiation has.

disa [49]3 years ago
6 0

Its actually C. I did the question on USA test prep and it said the correct answer was C.


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Roller coasters accelerates from initial speed of 6.0 M/S2 final speed of 70 M/S over four seconds. What is the acceleration?
choli [55]

Answer:

a=16\ m/s^2

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly in time.

The formula to calculate the change of velocities is:

v_f=v_o+at

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The roller coaster moves from vo=6 m/s to vf=70 m/s in t=4 seconds. To calculate the acceleration, solve for a:

\displaystyle a=\frac{v_f-v_o}{t}

\displaystyle a=\frac{70-6}{4}=\frac{64}{4}

\boxed{a=16\ m/s^2}

3 0
3 years ago
An infinitely long straight wire has a uniform linear charge density of Derive the 4. equation for the electric field a distance
marshall27 [118]

Answer:

E = \frac{\lambda}{2\pi \epsilon_0 r}

Explanation:

Let the linear charge density of the charged wire is given as

\frac{q}{L} = \lambda

here we can use Gauss law to find the electric field at a distance r from wire

so here we will assume a Gaussian surface of cylinder shape around the wire

so we have

\int E. dA = \frac{q}{\epsilon_0}

here we have

E \int dA = \frac{\lambda L}{\epsilon_0}

E. 2\pi r L = \frac{\lambda L}{\epsilon_0}

so we have

E = \frac{\lambda}{2\pi \epsilon_0 r}

4 0
3 years ago
1. What happens to particle spacing when temperature increase, What we call this process?
enot [183]

Answer:

Particle spacing increases and it's called evaporating

5 0
3 years ago
A tube of mercury with resistivity 9.84 × 10 -7 Ω ∙ m has an electric field inside the column of mercury of magnitude 23 N/C tha
slava [35]

Answer:

The current through the tube is 73.39A.

Explanation:

The relationship between the resistivity \rho, the electric field E, and the current density J is given by

\rho = \dfrac{E}{J}

This equation can be solved for J to get:

J = \dfrac{E}{\rho}

Since the current is I = J\cdot A

I= J\cdot A  = \dfrac{E}{\rho} \cdot A

Now, for the tube of mercury \rho = 9.84*10^{-7}\: \Omega \cdot m, E = 23N/C, and the area is A = \pi r^2 = \pi (1.0*10^{-3}m)^2 = 3.14*10^{-6}m^2; therefore,

I= \dfrac{23N/C}{9.84*10^{-7}\Omega\cdot m } *3.14*10^{-6}m^2

\boxed{I = 73.39A.}

Hence, the current through the mercury tube is 73.39A.

5 0
3 years ago
Please help me!!! ASAP 10 points for first to answer.
strojnjashka [21]
See the image above :)

7 0
3 years ago
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