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3 years ago

The energy pyramid below shows a possible

Chemistry

2 answers:

ExtremeBDS [4]3 years ago

7 0

Energy transfer is not an efficient process.

Explanation:

There is less amount of energy in the top of the energy pyramid than at the bottom because energy transfer is not an efficient process. During the process of energy transferring, some amount is lost and some are converted to other forms of energy.

The sun is the ultimate source of energy for all life in the solar system.
When autotrophs takes this energy, they produce food from it.
They use light energy from the sun to produce chemical energy in food.
Even this conversion process waste precious amount of energy.
As one goes up the pyramid, more energy is lost during the process of converting from one form to another.

Learn more:

laws of thermodynamics brainly.com/question/11769517

#learnwithBrainly

Brums [2.3K]3 years ago

6 0

Answer:

The correct answer is option A: "Energy is lost between each trophic level as heat".

Explanation:

The energy pyramid describes the amount of energy available at different trophic levels, where the producers have 1000 kilocalories of energy and the tertiary consumers have only 0.7 kilocalories. The energy lost between each trophic level is explained by the lost of energy as heat. When the organisms at a trophic level are consumed by the next trophic level, energy is lost in the form of metabolic heat. I attached the missing image.

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In a

dsp73

Answer:

1384 kJ/mol

Explanation:

The heat absorbed by the calorimeter is equal to the heat released due to the combustion of the organic compound. C is the total heat capacity of the calorimeter and Δt is the change in temperature from intial to final:

Q = CΔt = (3576 J°C⁻¹)(30.589°C - 25.000°C) = 19986.264 J

Extra significant figures are kept to avoid round-off errors.

We then calculate the moles of the organic compound:

(0.6654 g)(mol/46.07) = 0.0144432 mol

We then calculate the heat released per mole and convert to the proper units. (The conversion between kJ and J is infinitely precise and is not involved in the consideration of significant figures)

(19986.264 J)(1kJ/1000J) / (0.0144432 mol) = 1384 kJ/mol

8 0

4 years ago

How many protons, electrons, and neutrons does an atom with atomic number 50 and mass number 125 contain?

kherson [118]

The number of protons in an atom is equal the atomic number (= 50)

The sum of the Neutrons and Protons is the Atomic Mass (=125)
Neutrons + Protons=125

Plug in for the protons (50)
Neutrons +(50)=125

Then, once solved, we have Neutrons = 75

Assuming the atom is NOT an ion, the amount of electrons is equal to the number of protons. (protons=electrons=50=50)

Therefore:
There are 50 electrons, 50 protons, and 75 electrons.

5 0

3 years ago

The empirical formula for carbohydrates is CH2O. The molecular weight for a particular carbohydrate is 90.09 grams. What is the

baherus [9]

We find the weight of the empirical formula:
12.0107 + 2 x 1.00794 + 15.9994
= 30.03

Now, we divide the molecular weight by the weight of the empirical formula to find the number of times the empirical formula repeats:
90.09 / 30.03
= 3

The formula is 3(CH₂O)
C₃H₆O₃

6 0

4 years ago

Why don't we use meters or miles when discussion distances between stars or galaxies?

taurus [48]

If we use mile or something else it will be hard to measure in sky .
Because the mile or meters too short for the space,
Galaxy and stars are too long far away from us if we use mile or meter,
It till be take like miliion year to measure.

4 0

3 years ago

Given the following at 25C calculate delta Hf for HCN (g) at 25C. 2NH3 (g) +3O2 (g) + 2CH4 (g) ---> 2HCN (g) + 6H2O (g) delta

AysviL [449]

<u>Answer:</u> The $\Delta H_f$ for HCN (g) in the reaction is 135.1 kJ/mol.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]$

We are given:

$\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ$

Putting values in above equation, we get:

$-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ$

Hence, the $\Delta H_f$ for HCN (g) in the reaction is 135.1 kJ/mol.

8 0

3 years ago